我应该做些什么来防止自定义getaway的回调函数中的无效XML标记?
$h = fopen("banks/Mybank/log.txt", 'a');
fwrite($h, 'ConfirmRequest: '.print_r($_REQUEST['ConfirmRequest'],true)."\n");
fclose($h);
输出是:
ConfirmRequest: <ConfirmRequest><TransactionId> Cool Attitude #89</TransactionId><PaymentId>327600020200</PaymentId><PaymentDate>02.10.2013 23:41:26</PaymentDate><Amount>7000</Amount><CardType>VISA!472291******9871</CardType><Status>N</Status><Reason>Declined by merchant</Reason></ConfirmRequest>
结果在
上相同$_REQUEST['ConfirmRequest'];
和
$this->resuest->request['ConfirmRequest'];
==========================
非常感谢gloomy.penguin!你能告诉我,我在这里做错了什么?if(
!openssl_verify(
'ConfirmRequest='.$ConfirmRequest,
base64_decode($signature),
openssl_get_publickey($cert)
)
)
die("signature error");
$parser = xml_parser_create('');
xml_parser_set_option($parser, XML_OPTION_TARGET_ENCODING, "UTF-8");
xml_parser_set_option($parser, XML_OPTION_CASE_FOLDING, 0);
xml_parser_set_option($parser, XML_OPTION_SKIP_WHITE, 1);
xml_parse_into_struct($parser, $ConfirmRequest, $vals);
xml_parser_free($parser);
foreach ($vals as $data)
{
if ($data['tag']=='STATUS')
$Status=$data['value'];
if ($data['tag']=='PAYMENTID')
$PaymentId=$data['value'];
if ($data['tag']=='PAYMENTDATE')
$PaymentDate=$data['value'];
if ($data['tag']=='TRANSACTIONID')
$TransactionId=$data['value'];
if ($data['tag']=='AMOUNT')
$Amount=$data['value'];
if ($data['tag']=='REASON')
$Reason=$data['value'];
if ($data['tag']=='CARDTYPE')
$CardType=$data['value'];
}
$sta = fopen("banks/MyBank/status.txt", 'a');
fwrite($sta, .print_r($data)."\n");
fclose($sta);
输出值为“1”......
答案 0 :(得分:0)
这是您最初问题的答案:html_entity_decode()
由于您遇到与初始问题无关的新问题,我建议您关闭此问题(通过选择问题的答案)并针对您的新问题发布一个全新的帖子。包括您正在使用的代码以及变量中的内容,以便人们可以帮助您。