我用PHP创建了工作总时间程序 - 输入时间 - 1.30,2.10,1.40并获得输出时间 - 4.80(8小时)。但我需要输出时间 - 5.20(8.40小时)。 注意:1.30 + 2.10 + 1.40 = 4.80(8小时),但我需要5.20(8.40小时)。请帮帮我......
答案 0 :(得分:2)
1.30 + 2.10 + 1.40错了。应该是:
<(>(1 * 60)+ 30)+((2 * 60)+ 10)+((1 * 60)+40)= 320(分钟)320分钟= 5小时20分钟。
答案 1 :(得分:0)
您需要分别跟踪分钟和秒钟:
$minutes = array();
$seconds = array();
foreach ($times as $time) {
$parts = explode('.', $time);
$minutes[] = $time[0];
$seconds[] = $time[1];
}
$total_minutes = array_sum($minutes);
$total_seconds = array_sum($seconds);
while ($total_seconds > 60) {
$total_minutes++;
$total_seconds -= 60;
}
echo $total_minutes . ' minutes and ' . $total_seconds . ' seconds';
答案 2 :(得分:0)
摘自PHP网站:
function AddTime ($oldTime, $TimeToAdd) {
$pieces = split(':', $oldTime);
$hours=$pieces[0];
$hours=str_replace("00","12",$hours);
$minutes=$pieces[1];
$seconds=$pieces[2];
$oldTime=$hours.":".$minutes.":".$seconds;
$pieces = split(':', $TimeToAdd);
$hours=$pieces[0];
$hours=str_replace("00","12",$hours);
$minutes=$pieces[1];
$seconds=$pieces[2];
$str = $minutes." minute ".$seconds." second" ;
$str = "01/01/2000 ".$oldTime." am + ".$hours." hour ".$minutes." minute ".$seconds." second" ;
if (($timestamp = strtotime($str)) === false) {
return false;
} else {
$sum = date('h:i:s', $timestamp);
$pieces = split(':', $sum);
$hours = $pieces[0];
$hours = str_replace("12", "00", $hours);
$minutes = $pieces[1];
$seconds = $pieces[2];
$sum = $hours.":".$minutes.":".$seconds;
return $sum;
}
}
$firstTime = "00:03:12";
$secondTime = "02:04:34";
$sum=AddTime($firstTime, $secondTime);
if($sum != false) {
echo $firstTime." + ".$secondTime." = ".$sum;
} else {
echo "failed";
}
输出:
00:03:12 + 02:04:34 = 02:07:46
答案 3 :(得分:0)
对于每个号码(下面用$t
表示),您可以这样做:
// start with $total=0
$hours = floor($t); // 1.10 -> 1 hr
$minutes = ($t - $hours) * 100; // 1.10 -> 10 mins
$total += ($hours * 60) + $minutes;
这会给你总分钟数。要分别获得小时/分钟,请执行以下操作:
$total_mins = $total % 60; // 130 -> 10 mins
$total_hours = ($total - $total_mins) / 60; // 130 -> 2 hrs