Question

我在过去两天研究了这个主题，并尝试了多种尝试解决这个问题的方法。该程序假设采用16位随机密钥并将其与用户输入的消息进行异或。我的程序目前没有错误，但我遇到了问题。

import string
import random

message = raw_input("Enter your message: ").split(",")
size = 2    # or whatever lenght you want your random string to be
allowed = string.ascii_letters # add any other allowed characters here
randomstring = ''.join([allowed[random.randint(0, len(allowed) - 1)] for x in xrange(size)])

print
print("This is the key used for encryption:")
print randomstring #prints out key used
print
print("APPLYING XOR METHOD TO MESSAGE AND KEY")
print("--------------------------------------")

for i in xrange(0,len(message)-1):
    l += [ord(message) ^ ord(randomstring) for message,randomstring in zip(message,randomstring)]
print l

print

#BRUTE FORCE TO FIND OUT RANDOMSTRING
key= []
count =0
while(key!=randomstring):
    key = ''.join([allowed[random.randint(0, len(allowed) - 1)] for x in xrange(size)])
    count = count + 1
    if(key==randomstring):
        print ("FOUND KEY USED BY BRUTE FORCE: "+key)
        print (count)
        break

此代码生成随机密钥，并在for循环结束后找出相同的密钥。例如，我的输出是，

Enter your message: hi

This is the key used for encryption:
ng

APPLYING XOR METHOD TO MESSAGE AND KEY
--------------------------------------

FOUND KEY USED BY BRUTE FORCE: ng
1052

我需要一种方法将加密的XOR消息打印到屏幕上。提前谢谢！

Answer 1

首先，修改您对raw_input：

的电话

message = raw_input("Enter your message: ")

当您在输入字符串上调用.strip(",")时，您创建了一个字符串列表。因此，如果您最初输入“Hello，world”，则结果为['Hello', ' world']。

稍后在您的程序中，您需要message为字符串，而不是列表。

接下来，初始化变量l并在循环后打印其值：

l=[]
for i in xrange(0,len(message)-1):
    l += [ord(message) ^ ord(randomstring) for message,randomstring in zip(message,randomstring)]
print l

需要XOR ascii消息才能打印到屏幕

1 个答案: