我的按钮位于UITableViewCell旁边,我遇到了问题。我正在使用故事板并通过IB连接我的按钮。在我的cellforRowatIndexPath中,我向我的按钮添加了一个动作:
cell.likeBtnPressed.tag = indexPath.row;
[cell.likeBtnPressed addTarget:self action:@selector(userDidTapOnLikeButton:photo:) forControlEvents:UIControlEventTouchUpInside];
下面您将看到按下按钮时的调用内容:
-(void)userDidTapOnLikeButton:(UIButton *)button photo:(PFObject *)photo{
//Disable the button so users cannot send duplicat requests
[button setEnabled:NO];
[button setTintColor:[UIColor redColor]];
//Set the new state of the button
BOOL liked = !button.selected;
[button setEnabled:liked];
//Get the current number of likes the post have
NSString *originalButtonTitle = button.titleLabel.text;
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en_US"]];
//Update the like count in the ECDCache
NSNumber *likeCount = [numberFormatter numberFromString:button.titleLabel.text];
if (liked) {
likeCount = [NSNumber numberWithInt:[likeCount intValue] + 1];
[[ECDCache sharedCache] incrementLikerCountForPhoto:photo];
}else{
if ([likeCount intValue] > 0) {
likeCount = [NSNumber numberWithInt:[likeCount intValue] - 1];
}
[[ECDCache sharedCache] decrementLikerCountForPhoto:photo];
}
//Add the current user as a liker of the photo in ECDCache
[[ECDCache sharedCache] setPhotoIsLikedByCurrentUser:photo liked:liked];
//Update the button label
[button setTitle:[numberFormatter stringFromNumber:likeCount] forState:UIControlStateNormal];
//Call the appropriate static method to handle creating/deleting the right object
if (liked) {
[ECDUtility likePhotoInBackground:photo block:^(BOOL succeeded, NSError *error) {
[button setEnabled:YES];
[button setTitleEdgeInsets:UIEdgeInsetsMake(-1.0f, 0.0f, 0.0f, 0.0f)];
[[button titleLabel] setShadowOffset:CGSizeMake(0.0f, -1.0f)];
if (!succeeded) {
// Revert the button title (the number) if the call fails
[button setTitle:originalButtonTitle forState:UIControlStateNormal];
}
}];
}
}
当我按下按钮时,我会收到:
-[UITouchesEvent objectId]: unrecognized selector sent to instance 0x15ee5de0
我不确定我做错了什么
答案 0 :(得分:1)
问题是您的方法接收的第二个参数不是PFObject
,而是UIEvent
。
您可以向addTarget:action:forControlEvents:
发送三种类型的选择器:
@selector(a)
:此方法不带参数。@selector(a:)
:此方法有一个参数,即接收控制事件的UIControl
。@selector(a:b:)
:此方法有两个参数,即收到控件事件的UIControl
和触发它的UIEvent
。由于您只想获得按钮,因此您应该有这样的签名:
-(void)userDidTapOnLikeButton:(UIButton *)button
{
PFObject *photo = [self someLogicToGetThePhotoFromTheButton:button];
...
答案 1 :(得分:0)
您无法在UIButton选择器中添加具有多个参数的目标。当调用选择器时,只接收sender参数,在这种情况下,接收UIButton对象。所以我建议您使用:
[cell.likeBtnPressed addTarget:self action:@selector(userDidTapOnLikeButton:photo:) forControlEvents:UIControlEventTouchUpInside];
-(void)userDidTapOnLikeButton:(id)sender{
//Your code
}
然后使用单元格的标签检索照片。
祝你好运;)