运行存储过程的PhpMyAdmin通过接口工作,但作为查询运行不起作用

时间:2013-10-02 12:36:32

标签: php mysql phpmyadmin

最奇怪的事情刚刚发生:

这是我在PhpMyAdmin MySql界面中编写的SP:

Begin
    /* event id and number of event's albums*/
    Declare eventId varchar(20);
    /*Declare numberOfAlbums int default 0;     */
    /* get event id */
    Set eventId = decodeEventCode(eventCode);

    If (eventKey Is Not Null And eventKey <> '' And getEventKey(eventId,facebookId) = eventKey) Then                
        /* get number of albums */
        /*Set numberOfAlbums = (Select Count(eventId) From Albums Where Event_Id = eventId);*/
        /* return active album */
        Select Users.Facebook_Id, Users.Facebook_Access_Token, Users.Facebook_Expires, getUserTime(facebookId) As User_Local_Time, Events.Name as Event_Name, Events.Place As Event_Place, Events.Start_Time, Events.End_Time, Albums.Album_Id, Albums.Number_Of_Pictures/*, numberOfAlbums As Album_Count*/
        From Albums
        Inner Join Events
        On Events.Event_Id = Albums.Event_Id
        Inner Join Users
        On Users.Facebook_Id = Events.Facebook_Id
        Where Albums.Event_Id = eventId
        Order By Albums.Number_Of_Pictures
        Limit 1;
        /* if no rows was found return 0*/      
        If (Found_Rows() = 0) Then      
            select 0 as status;
        End If;
    Else
        Select 0 as status;
    End If;
End

这是使用PhpMyAdmin中的“执行”按钮的结果。注意界面生成的查询:

This is how the result using the "Execute" button in the PhpMyAdmin looks like. pay attention to the query the interface has generated

这是我正在复制/粘贴的确切查询,并在PhpMyAdmin SQL Query界面中用于测试它 - 并且它没有选择任何表示没有找到表的地方:

This is the exact query being copy/paste by me and used in the PhpMyAdmin SQL Query interface in order to test it - and it select nothing saying no tables were found...

这是我的php代码:

/**
 * Get the current active event album with all his details
 * @param $eventCode string the event code of the event
 * @param $eventKey string the user's special event key
 * @param $facebookId string user's facebook id
 * @return array the details of the active album
 */
function getEventActiveAlbum($eventCode,$eventKey,$facebookId)
{
    return $this->queryDb("Call getEventActiveAlbum('$eventCode','$eventKey','$facebookId')");
}

生成查询:

Call getEventActiveAlbum('10230910','42','613714903')

知道为什么会这样吗?从PHP代码运行脚本时,我什么也得不回来......

3 个答案:

答案 0 :(得分:1)

好的,我解决了它:

问题在于select语句。

当没有结果时 - 这个问题中提到的问题发生了,但是,当有结果时 - 它工作正常。

我已经重写了我的存储过程并使用Select Count()来确定我是否应该尝试运行复杂的select语句,如下所示:

Begin
    /* declare eventId and number of albums for this event */
    Declare eventId int;
    Declare numberOfAlbums int default 0;

    /*get event id */
    Set eventId = decodeEventCode(eventCode);
    /* if event id is valid, and event key is correct */
    If (eventId <> -1 And eventKey Is Not Null And getEventKey(eventId,facebookId) <> 0) Then
        /*count the number of albums in this event */
        Set numberOfAlbums = (Select Count(Album_Id) From Albums Where Event_Id = eventId); 
        /* if there are albums in these event - return the active one*/
        if (numberOfAlbums > 0) Then
            Select Events.Name as Event_Name, Events.Place as Event_Place, Events.Start_Time, Events.End_Time,
                   getUserTime(Users.Facebook_Id) as User_Local_Time, Users.Facebook_Id, Users.Facebook_Access_Token, Users.Facebook_Expires,
                    Albums.Album_Id, Albums.Number_Of_Pictures, numberOfAlbums as Albums_Count
            From Albums
            Inner Join Events
            On Albums.Event_Id = Events.Event_Id
            Inner Join Users
            On Events.Facebook_Id = Users.Facebook_Id
            Where Albums.Event_Id = eventId
            Order By Albums.Number_Of_Pictures 
            Limit 1;
        /* if there are no albums in the event - return event details */
        Else
            Call getEventDetails(eventCode);
        End If;
    /* if the request is not valid - return 0 as status */
    Else    
        Select 0 as status;
    End If;     
End

答案 1 :(得分:0)

我会写作答案,因为我需要空间

也许您的框架/类使查询$this->queryDb使用较旧的mysql而不是较新的mysqli。为了它的乐趣,试试

$conn = mysqli_connect("hostname", "user", "password", "db", "port");      
$result = mysqli_query(
  $conn,
  "Call getEventActiveAlbum('$eventCode','$eventKey','$facebookId')"
)
or die("failed: " . mysqli_error());

ps mysql中没有大师

答案 2 :(得分:0)

我遇到过类似的问题。我猜这是由于分隔符的问题。尝试使用原始的mysql控制台而不是phpMyadmin创建存储过程。