请求规范发布请求没有路由匹配错误

时间:2013-10-02 12:19:27

标签: ruby-on-rails ruby rspec ruby-on-rails-4

我没有与rspec匹配路由来测试我的控制器中的方法。

以下是测试代码:

let(:csv_file){ fixture_file_upload('files/sample_employee_data.csv', 'text/csv') }
    describe "#process_csv" do
      it "should output a valid csv file" do
        post '/payslips/process_csv', :csv => csv_file, :header => 1
        puts response
      end
    end

以下是我的routes.rb文件代码:

PayCalculator::Application.routes.draw do
  resources :payslips do
    collection { post :process_csv }
  end

  root 'payslips#index'
end

以下是方法

def process_csv(uploaded_file = params[:files][:csv], headers = params[:files][:headers])
    begin
      rows = CSV_Manager.extract_csv(uploaded_file, headers)
      rows.each do |row|
        payslip = Payslip.create(
            :first_name => row[0],
            :last_name => row[1],
            :annual_salary => row[2],
            :superannuation => row[3].to_i,
            :payment_start_date => row[4]
            )

        redirect_to root_url, notice: payslip.errors.full_messages and return unless payslip.valid?
        prepare_output(row)
      end

      @rows = self.pay_data
      csv_file = CSV_Manager.prepare_csv(@rows, ["Name", "Pay Period", "Gross Income", "Income Tax", "Net Income", "Superannuation"])
      send_data csv_file, :type => 'text/csv; charset=iso-8859-1; header=present', 
                          :disposition => "attachment;filename=Payslip #{Date.today.to_s}.csv"

    rescue 
      redirect_to root_url, notice: "CSV not supplied or invalid format"
    end
  end

当我运行rspec spec/时,我得到以下错误:

Failure/Error: post '/payslips/process_csv', :csv => csv_file, :header => 1

ActionController::UrlGeneratorError:
No route matches...

导致此错误的可能是什么错误?

2 个答案:

答案 0 :(得分:0)

试试这个:

post :process_csv, :files => {:csv => csv_file, :header => 1}

答案 1 :(得分:0)

params[:files][:headers]您传递:header => 1的地方。关键是不同的。这不会导致找不到路线,只是为了纠正。根据rails约定,action没有参数

如果您打算以任何方式传递可选参数:请查看:http://www.ruby-doc.org/docs/ProgrammingRuby/html/tut_methods.html

以下是方法定义的例子:

def foo(arg1="Miles", arg2="Coltrane", arg3="Roach")
  "#{arg1}, #{arg2}, #{arg3}."
end
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