我有这个表格结构,我无法改变:
<table class="sui-opt-in">
<tbody>
<tr>
<th></th>
<th><strong>Time</strong>
</th>
<th><strong>Cost</strong>
</th>
</tr>
<tr style="display: none;" id="labor_summary_for_1">
<td> <a href="#" onclick="jQuery('#labor_for_1').show(); jQuery('#labor_summary_for_1').hide(); return false;">
<i class="icon-right "></i>
Name Here
</a>
</td>
<td>1m</td>
<td>£0.75</td>
</tr>
</tbody>
<tbody id="labor_for_1" style="display: table-row-group;">
<tr>
<td> <a href="#" onclick="jQuery('#labor_summary_for_1').show(); jQuery('#labor_for_1').hide(); return false;">
<i class="icon-down "></i>
Name Here
</a>
</td>
<td></td>
<td></td>
</tr>
<tr>
<td></td>
<td>1m</td>
<td>£0.75 <a href="#" onclick="new Ajax.Request('/tickets/remove_time_spent/1247', {asynchronous:true, evalScripts:true, method:'delete', parameters:'work_id=456&selected_view=my_tickets' + '&authenticity_token=' + encodeURIComponent('7hd72GGlOMJINFvnvio5c6z0CTtRyxNUdU8uMJrKhps=')}); return false;"><i class="icon-remove "></i></a>
</td>
</tr>
</tbody>
<tfoot>
<tr>
<td><strong>Total</strong>
</td>
<td><strong>1m</strong>
</td>
<td><strong>£0.75</strong>
</td>
</tr>
</tfoot>
</table>
然后我用这个jQuery删除最后一个表格单元格:
jQuery("#labor-section .sui-opt-in th:last-child, #labor-section .sui-opt-in td:last-child").remove();
但不是我只想在最后一个单元格上保留一个href(取消价格)。
有什么建议吗?
感谢。
答案 0 :(得分:2)
尝试
jQuery('#labor-section .sui-opt-in').find('th:last-child, td:last-child').contents().filter(function(){
return this.nodeType == 3
}).remove();
演示:Fiddle