Question

我把python文件和＆＃39; g1.txt＆＃39;在同一目录中。当我不使用SublimeREPL

时，代码可以正常运行

def build_graph(file_name):
    new_file = open(file_name, 'r')
    n, m = [int(x) for x in new_file.readline().split()]

    graph = {}
    for line in new_file:
        # u, v, w is the tail, head and the weight of the a edge
        u, v, w = [int(x) for x in line.split()]
        graph[(u, v)] = w

    return n, graph

if __name__ == '__main__':
    print build_graph('g1.txt')

>>> >>> Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<string>", line 18, in <module>
  File "<string>", line 6, in build_graph
IOError: [Errno 2] No such file or directory: 'g1.txt'

Answer 1

试试这个：

 import os
 build_graph(os.path.join(os.path.dirname(__file__),"g1.txt"))

它会将脚本的目录附加到g1.txt

Answer 2

扩展此answer，SublimeREPL不一定使用g1.txt所在的同一工作目录。您可以使用

import os
build_graph(os.path.join(os.path.dirname(__file__),"g1.txt"))

如前所述，或者以下内容也适用：

if __name__ == '__main__':
    import os
    os.chdir(os.path.dirname(__file__))
    print build_graph('g1.txt')

只是一件小事，但您也不会关闭文件描述符。您应该使用with open()格式：

def build_graph(file_name):
    with open(file_name, 'r') as new_file:
        n, m = [int(x) for x in new_file.readline().split()]

        graph = {}
        for line in new_file:
            # u, v, w is the tail, head and the weight of the a edge
            u, v, w = [int(x) for x in line.split()]
            graph[(u, v)] = w

    return n, graph

这将在您完成后自动关闭文件描述符，因此您不必担心手动关闭它。保持文件打开通常是一个坏主意，特别是如果你正在写文件，因为当你的程序结束时它们可能会处于不确定的状态。

python：IOError：[Errno 2]使用sublimeREPL时没有这样的文件或目录

2 个答案: