输入行具有以下值(例如,仅显示2行,但可能有更多行;当然值可能不同)
entry_id | transaction_partner_name | registration_number
values
10 name 1 number 1
11 name 2 number 2
必须使用值
更新mysql表查询可能是这样的
UPDATE 2_1_transactionpartners SET
CompanyName = CASE NumberRenamed
WHEN ? THEN ? WHEN ? THEN ?
END,
RegistrationNumber = CASE NumberRenamed
WHEN ? THEN ? WHEN ? THEN ?
END
WHERE NumberRenamed in (?,?)
或
$sql = "
UPDATE 2_1_transactionpartners SET
CompanyName = CASE NumberRenamed
$when_then
END,
RegistrationNumber = CASE NumberRenamed
$when_then
END
WHERE NumberRenamed in ($placeholders_for_number_renamed)";
现在在foreach中创建变量
$entry_id_for_number_renamed = array();
foreach ($_POST['entry_id'] as $i => $entry_id) {
$for_company_name .= ( $_POST['entry_id'][$i]. ','. $_POST['transaction_partner_name'][$i]. ',' );
$for_registration_number .= ( $_POST['entry_id'][$i]. ','. $_POST['registration_number'][$i]. ',' );
$entry_id_for_number_renamed[] = $_POST['entry_id'][$i];
$when_then .= 'WHEN ? THEN ? ';
$placeholders_for_number_renamed .= '?,';
}
$for_company_name = rtrim($for_company_name, ',');
$for_company_name = explode(',', $for_company_name);
$for_registration_number = rtrim($for_registration_number, ',');
$for_registration_number = explode(',', $for_registration_number);
$insertData = array_merge( $for_company_name, $for_registration_number, $entry_id_for_number_renamed );
如果想要更好(更短)的解决方案,请咨询
答案 0 :(得分:1)
UPDATE transactionpartners
SET transaction_partner_name = q.transaction_partner_name,
registration_number = q.registration_number
FROM (
SELECT 10 AS entry_id ,
'new name 1' AS transaction_partner_name,
'new number 2' AS registration_number
UNION
SELECT 11 AS entry_id ,
'new name 3' AS transaction_partner_name,
'new number 4' AS registration_number
)
q
WHERE q.entry_id = transactionpartners.entry_id