访问Angular.js中的另一个控制器

时间:2013-10-01 23:05:02

标签: javascript json angularjs

到目前为止我的基本代码:

function UsersCtrl($scope) {
    $scope.users = [
        {
            "id": 1,
            "usersName": "Matt Dance",
            "favorites": {
                "id":1,
                "lodge_id":1
            }
        },
        {
            "id":2,
            "usersName": "Jennifer Dance",
            "favorites": {
                "id":1,
                "lodge_id":2
            }
        }
    ];
};

function LodgesCtrl($scope) {
    $scope.lodges = [
        {
            id: 1,
            lodgesName: 'Matt\'s Awesome Lodge',
            lodgeOwnersName: 'Matthew D',
            lodgeStreetAddress: '5555 J lane',
            lodgeCity: 'Salt Lake city',
            lodgeZip: '11111',
            lodgeState: 'Utah'
        },
        {
            id: 2,
            lodgesName: 'Some Historic Lodge',
            lodgeOwnersName: 'Santa Claus',
            lodgeStreetAddress: '1 Clearwater Road',
            lodgeCity: 'Grand Marais',
            lodgeZip: '55555',
            lodgeState: 'Minnesota'
        },
        {
            id: 3,
            lodgesName: 'Yellowstone Lodge',
            lodgeOwnersName: 'The Feds',
            lodgeStreetAddress: '1 Yellowstone Way',
            lodgeCity: 'Yellowstone',
            lodgeZip: '55555',
            lodgeState: 'Wyoming'
        },
        {
            id: 4,
            lodgesName: 'Cool Lodge',
            lodgeOwnersName: 'Awesome Guy',
            lodgeStreetAddress: '1 awesome Road',
            lodgeCity: 'Eagle Mountain',
            lodgeZip: '55555',
            lodgeState: 'Utah'
        },
        {
            id: 5,
            lodgesName: 'The last lodge',
            lodgeOwnersName: 'Adam V',
            lodgeStreetAddress: '444 Last Road',
            lodgeCity: 'San Francisco',
            lodgeZip: '55555',
            lodgeState: 'California'
        }
    ];
};

我希望用户能够看到他们所喜欢的小屋的小屋名称。例如,用户喜欢id为1的小屋。然后我可以循环浏览每个用户,并显示最喜欢的小屋的标题?基本上,我需要为他们收藏夹中的每个用户使用lodge_id来显示小屋名称。

我的html到目前为止:

<div ng-controller="UsersCtrl">
<ul class="unstyled">
  <li ng-repeat="user in users">
    {{user.usersName}}<br>
  </li>
</ul>
</div>

我是Angular(以及一般的JS框架)的新手,我不知道如何解决这个问题。我已经研究过像Ember这样的其他框架,但却无法以“简单”的方式解决它。

3 个答案:

答案 0 :(得分:1)

最简单的解决方案是构造一个映射对象并将其绑定到$ rootScope。例如:

$rootScope.mapping = {
    userId: [lodge1, lodge2...]
}

答案 1 :(得分:0)

我对您的代码进行了一些更改,现在它正在运行但我认为您需要以更好的方式构建数据,以便您可以更轻松地进行迭代。

你也可以在这里看到一个工作的傻瓜(http://plnkr.co/edit/DtBxzYulJGTQC0KJsh8M?p=preview)。

 <!doctype html>
 <html lang="en" ng-app="myApp">
    <head>
<meta charset="UTF-8">
<title>Document</title>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.0.8/angular.min.js"></script>

<script>

var myApp = angular.module('myApp', []);

myApp.controller('UsersCtrl', ['$scope', function ($scope) {
    $scope.users = [
        {
            "id": 1,
            "usersName": "Matt Dance",
            "favorites": {
                "id":1,
                "lodge_id":1
            }
        },
        {
            "id":2,
            "usersName": "Jennifer Dance",
            "favorites": {
                "id":1,
                "lodge_id":2
            }
        }
    ];

    $scope.lodges = [
        {
            id: 1,
            lodgesName: 'Matt\'s Awesome Lodge',
            lodgeOwnersName: 'Matthew D',
            lodgeStreetAddress: '5555 J lane',
            lodgeCity: 'Salt Lake city',
            lodgeZip: '11111',
            lodgeState: 'Utah'
        },
        {
            id: 2,
            lodgesName: 'Some Historic Lodge',
            lodgeOwnersName: 'Santa Claus',
            lodgeStreetAddress: '1 Clearwater Road',
            lodgeCity: 'Grand Marais',
            lodgeZip: '55555',
            lodgeState: 'Minnesota'
        },
        {
            id: 3,
            lodgesName: 'Yellowstone Lodge',
            lodgeOwnersName: 'The Feds',
            lodgeStreetAddress: '1 Yellowstone Way',
            lodgeCity: 'Yellowstone',
            lodgeZip: '55555',
            lodgeState: 'Wyoming'
        },
        {
            id: 4,
            lodgesName: 'Cool Lodge',
            lodgeOwnersName: 'Awesome Guy',
            lodgeStreetAddress: '1 awesome Road',
            lodgeCity: 'Eagle Mountain',
            lodgeZip: '55555',
            lodgeState: 'Utah'
        },
        {
            id: 5,
            lodgesName: 'The last lodge',
            lodgeOwnersName: 'Adam V',
            lodgeStreetAddress: '444 Last Road',
            lodgeCity: 'San Francisco',
            lodgeZip: '55555',
            lodgeState: 'California'
        }
    ];
   }]);


   </script>

    </head>
    <body>

 <div ng-controller="UsersCtrl">
 <ul>
  <li ng-repeat="user in users">
    {{user.usersName}}<br>
    {{user.favorites.lodge_id}}<br>
        <p ng-repeat="lodge in lodges | filter: { id: user.favorites.lodge_id }">
            {{lodge.lodgesName}}
        </p>
  </li>
</ul>
</div>

 </body>
 </html>

答案 2 :(得分:0)

您应该使用服务。由于服务是单件,因此它们是在控制器之间共享内容的最简单方法。事实上,这是有角度的方式:

  

请勿将控制器用于:

     

跨控制器共享无状态或有状态代码 - 使用angular   相反,服务。

Developer Guide/Understanding the Controller Component