我有三张桌子 - 商店,土豆和番茄(番茄桌看起来像土豆桌)。马铃薯桌上的身份确实是商店的身份 - 所以那个商店的马铃薯的价格。
+----+-------+-----------+
| potato |
+----+-------+-----------+
| id | price | date_time |
+----+-------+-----------+
+----+-----+-----+------+------+
| shop |
+----+-----+-----+------+------+
| id | lat | lng | name | geom |
+----+-----+-----+------+------+
我想做的是选择距离某个位置最多10公里的所有商店,以及番茄和土豆价格。
现在,我有这个查询,可以选择商店,以及土豆价格
SELECT
shop.lat,
shop.lng,
shop.id,
potato.date_time AS potato_date,
potato.price as potato_price
FROM
shop,
potato
WHERE
potato.id = shop.id AND
ST_DWithin(
ST_GeomFromText('POINT(xx.xxxxxx yy.yyyyyy)',4326),
shop.geom,
10*1000,
true
);
但是我想得到那家商店的番茄价格。怎么可能呢?
答案 0 :(得分:3)
使用Left JOIN
SELECT
shop.lat
, shop.lng
, shop.id
, potato.date_time AS potato_date
, potato.price as potato_price
, tomato.date_time as tomato_date
, tomato.price as tomato_price
FROM shop
LEFT JOIN potato on potato.ID = shop.ID
LEFT JOIN tomato on tomato.ID = shop.ID
WHERE ST_DWithin(ST_GeomFromText('POINT(xx.xxxxxx yy.yyyyyy)',4326), shop.geom,10*1000, true );
如果每家商店都出售西红柿和土豆,你可以使用内部连接。