Question

我正在尝试为mvc项目设置spring security，我很难过。我正在使用spring security 3.1.4。请。我设置了一个spring-security.xml文件，并设置了mvc-dispatcher-servlet文件进行配置。现在我正在为我的用户详细信息Bean找到一个bean找不到异常。

在intellij中，我收到了myUserDetailService的“无法解析bean”消息。我也无法解析包“控制器”。运行项目时的根错误是：

Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.security.authentication.dao.DaoAuthenticationProvider#0': Cannot resolve reference to bean 'myUserDetailService' while setting bean property 'userDetailsService'; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'myUserDetailService' is defined
    at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:329) [spring-beans-3.2.0.RELEASE.jar:3.2.0.RELEASE]
    at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:107) [spring-beans-3.2.0.RELEASE.jar:3.2.0.RELEASE]

这是我的spring-security.xml文件：

<beans:beans xmlns="http://www.springframework.org/schema/security"
         xmlns:beans="http://www.springframework.org/schema/beans"
         xmlns:context="http://www.springframework.org/schema/context"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
         xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
       http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">


<!-- Enabling Spring beans auto-discovery -->
   <context:component-scan base-package="controller, com.company.admin" />

<http auto-config="true">
    <intercept-url pattern="/admin/*" access="ROLE_USER"  />
    <form-login login-page="/login" default-target-url="/admin/welcome"   authentication-failure-url="/loginfailed" />
    <logout logout-success-url="/logout" />
</http>

<authentication-manager>
    <authentication-provider user-service-ref="myUserDetailService"/>
</authentication-manager>

</beans:beans>

这是我的mvc-dispatcher-servlet.xml：

<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xmlns:context="http://www.springframework.org/schema/context"
   xmlns:mvc="http://www.springframework.org/schema/mvc"
   xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">


<!-- Enabling Spring beans auto-discovery -->
<context:component-scan base-package="com.company.admin" />

<!-- Enabling Spring MVC configuration through annotations -->
<mvc:annotation-driven />

<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/WEB-INF/pages/"/>
    <property name="suffix" value=".jsp"/>
</bean>
</beans>

这是我的web.xml：

<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<display-name>Spring MVC Application</display-name>


<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        /WEB-INF/mvc-dispatcher-servlet.xml,
        /WEB-INF/spring-security.xml
    </param-value>
</context-param>

<servlet>
    <servlet-name>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>mvc-dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<listener>
    <listener-class>
        org.springframework.web.context.ContextLoaderListener
    </listener-class>
</listener>
</web-app>

我基本上都在尝试遵循这个教程：http://kh-yiu.blogspot.com/2012/12/spring-mvc-security-custom.html和UserDetailServiceImpl完全相同，但我确实在main / java目录中的不同文件夹中。重要的是要注意我使用注释来声明类：

@Service("myUserDetailService")
public class UserDetailsServiceImpl implements UserDetailsService{

有什么想法吗？我很难找到与我正在使用的弹簧版本相同的教程，所以我很可能搞乱了xsd refs。感谢。

Answer 1

您正在添加对以下内容的引用：

<authentication-provider user-service-ref="myUserDetailService"/>

你需要一个带有那个id的bean ......比如：

<bean id="myUserDetailService" class="the.class.of.your.service"></bean>

稍等一下你的例外：

//Error creating the bean
Caused by: org.springframework.beans.factory.BeanCreationException: 
Error creating bean with name 'org.springframework.security.authentication.dao.DaoAuthenticationProvider#0': 
//The myUserDetailService reference cannot be solved, it cannot be found or it has syntax error or something is wrong there
Cannot resolve reference to bean 'myUserDetailService' while setting bean property 'userDetailsService'; 
//The root cause is an exception deeper.
nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: 
//You don't have a bean with this name:
No bean named 'myUserDetailService' is defined

更新：

现在你添加了@Service myUserDetailService ......它可能是why does annotate class as @Service do not create bean?的重复

spring security bean未找到异常

1 个答案: