我尝试显示以1或0结尾的所有行，并使用grep显示行中最后一个字符的第3行中的1。
01 m motzart amadeous 25 2nd 94233 02 m guthrie woody 23 2nd 94223 03 f simone nina 27 2nd 94112 04 m lennon john 29 2nd 94221 05 f harris emmylou 20 2nd 94222 06 m marley bob 22 2nd 94112 07 f marley rita 26 2nd 94212 08 f warwick dione 26 2nd 94222 09 m prine john 35 3rd 94321 10 m franti michael 34 3rd 94112 11 f black mary 21 2nd 94221 12 m dylan bob 37 3rd 94311 13 f baez joan 36 3rd 94311 14 m richards keith 42 4th 94112 15 m jagger mick 41 4th 95115 16 m mcdonald countryjoe 46 4th 94543 17 f chapman tracy 43 4th 94211 18 m springstein bruce 45 4th 94323 19 f mitchell joni 40 4th 94444 20 f walker alice 37 3rd 94332 21 f oliver mary 47 4th 94114 22 m kotzwinkle william 44 4th 94433 23 f kate wilhelm 73 7th 94778 24 m heinlein robert 74 7th 94765 25 m asimov isaac 75 7th 94777 26 m moose bullwinkle 16 1st 94111 27 m squirrel rocketJ 17 1st 94122 28 f fenwich nell 13 1st 94221 29 m peobody mr 18 1st 94222 30 m longlastname longfirstname 11 1st 94313 31 m leaves t 22 2nd 94223 32 m hanh thichNhat 26 2nd 94115 33 m chomsky noam 34 3rd 94116 34 m morrison norman 71 7th 94771 35 f anthony susanB 48 4th 94321 36 m kropotkin peter 49 4th 94115 37 m gandhi mohatmas 53 5th 95123 38 f tubman harriet 50 5th 95555 39 m king martinLuther 52 5th 95112 40 m chavez cesar 57 5th 95112 41 m douglas frederick 66 6th 94666 42 f goldman emma 64 6th 94611 43 f mandela nelson 60 6th 96543 44 f parks rosa 72 7th 94777 45 m russell bertrand 55 5th 94113 46 f lovelace ada 56 5th 95123 47 m darwin charles 59 5th 95123 48 m galileo galileli 58 5th 95113 49 m einstein albert 54 5th 94113
这是文件
答案 0 :(得分：2)
这应该这样做：
grep '1.[10]$' filename
我创建了以下测试输入文件：
198273789120 123981298371 239817239111 123981239871 192873698127
并运行上面的grep命令，得到了这个输出：
198273789120 239817239111
打印的两行以0或1结尾，并以1作为行的倒数第3个字符。
答案 1 :(得分：0)
你可以试试这个
egrep -e '1.(1|0)$' your_file
返回以1或1结尾的任何行，并在第3位到最后位置处有1。