Question

给出以下字符串：

string = @"
/SQL "\Geneva\GenevaAfterTaxExtracts" /SERVER SMAMSQL2602A /CHECKPOINTING OFF 
/SET "\Package.Variables[User::Portfolio].Properties[Value]";"2504,2505,2506,2507,336,339,340,343,344,345,346,348,349,350" 
/SET "\Package.Variables[User::FirstMonthEnd].Properties[Value]";"8/31/2013" 
/SET "\Package.Variables[User::LastMonthEnd].Properties[Value]";"8/31/2013" 
/SET "\Package.Variables[User::Files].Properties[Value]";"Valuations" /REPORTING E"

我想匹配和nextMatch如下：

/SET "\Package.Variables[User::Portfolio].Properties[Value]";"2504,2505,2506,2507,336,339,340,343,344,345,346,348,349,350" 
/SET "\Package.Variables[User::FirstMonthEnd].Properties[Value]";"8/31/2013" 
/SET "\Package.Variables[User::LastMonthEnd].Properties[Value]";"8/31/2013" 
/SET "\Package.Variables[User::Files].Properties[Value]";"Valuations"

我使用以下内容：

Regex re = new Regex(@"\/SET ([^\/]+)");
Match match = re.Match(command);

第一个和最后一个工作正常，但是在＆＃39; /＆＃39;之前被截断的日期如下图所示

/SET "\Package.Variables[User::FirstMonthEnd].Properties[Value]";"8

/SET "\Package.Variables[User::LastMonthEnd].Properties[Value]";"8

如何更改正则表达式（@＆＃34; / SET（[^ /] +）＆＃34;）以及它在日期上匹配的方式？

提前致谢。

Answer 1

如果它们是单独的行

/SET.*

如果他们在同一条线上

/SET.*?(?=/[a-zA-Z]+|$)

List<String> output=Regex.Matches(input,regex)
                         .Cast<Match>()
                         .Select(x=>x.Value)
                         .ToList();

Answer 2

这个正则表达式怎么样：

Regex re = new Regex(@"\/SET (.+?)(?=( *\/[a-z]| *$))");

如何使用正则表达式正则表达式匹配某些字符串

2 个答案: