Question

我有一个故障的ToggleButton。据我了解，单击时应检查ToggleButton，再次单击时应取消选中。

此示例中的ToggleButton没有。单击它只是将其设置为再次检查。任何想法为什么？

<Page xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
  xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
  <Grid>  
        <ToggleButton Width="100" Height="35"  Name="btnAddLinkComment" >           
             <CheckBox Content=" Comment" FlowDirection="RightToLeft" IsHitTestVisible="False" 
                       Focusable="False" IsChecked="{Binding ElementName=txtLinkComment,  Path=Text}" 
                       Name="chkHasComment" Margin="5"/>
        </ToggleButton>
        <Popup IsOpen="{Binding ElementName=btnAddLinkComment,Path=IsChecked}"  
               PlacementTarget="{Binding ElementName=btnAddLinkComment}"  Name="popAddCommentLink"
               AllowsTransparency="True" StaysOpen="False" PopupAnimation="Fade"  HorizontalOffset="-50"
               VerticalOffset="50">
            <Border BorderBrush="#FF000000" Background="LightBlue" BorderThickness="1,1,1,1" 
                    CornerRadius="8,8,8,8" Padding="5">
                <Grid Background="LightBlue">
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition Width="80"></ColumnDefinition>
                        <ColumnDefinition Width="200"></ColumnDefinition>
                    </Grid.ColumnDefinitions>
                    <TextBlock TextWrapping="Wrap" Foreground="Black">Enter Link Comment:</TextBlock>
                    <TextBox Grid.Column="1" Name="txtLinkComment" Width="200"></TextBox>
                </Grid>
            </Border>
        </Popup>
  </Grid>
</Page>

Answer 1

我猜这是因为弹出窗口被弯曲到btnAddLinkComment.isChecked属性。我相信当你显示弹出窗口时，你点击按钮会使它关闭，并将按钮的IsChecked字段设置为false，这会使按钮处于无遮挡状态;然后点击由按钮本身处理，因为它没有切换，它变为切换，弹出再次显示。我想你可以通过删除绑定来解决问题，并在代码中进行一些处理;像这样的人：

btnAddLinkComment.Click += btnAddLinkComment_Click;
popAddCommentLink.Closed += popAddCommentLink_Closed;

private void btnAddLinkComment_Click(object sender, RoutedEventArgs e)
{
    if (popAddCommentLink.IsOpen && btnAddLinkComment.IsChecked == false)
        popAddCommentLink.IsOpen = false;
    else if (!popAddCommentLink.IsOpen && btnAddLinkComment.IsChecked == true)
        popAddCommentLink.IsOpen = true;
}

private void popAddCommentLink_Closed(object sender, EventArgs e)
{
    btnAddLinkComment.IsChecked = false;
}

希望这有帮助，尊重

Answer 2

我不完全确定你想要完成什么，但下面的代码可能是朝着正确方向迈出的一步。请详细说明！

<Window x:Class="ToggleButtonSpike.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="300"
    xmlns:local="clr-namespace:ToggleButtonSpike">
    <Window.Resources>
        <local:TextToBool x:Key="StringToBool"/>
    </Window.Resources>
    <StackPanel>
        <ToggleButton Name="Toggle" >
            <CheckBox IsHitTestVisible="False"
                Content="{Binding ElementName=Comment, Path=Text,
                UpdateSourceTrigger=PropertyChanged}"
                IsChecked="{Binding ElementName=Comment, Path=Text,
                Converter={StaticResource StringToBool}}"/>
        </ToggleButton>
        <Popup IsOpen="{Binding ElementName=Toggle, Path=IsChecked}"
               PlacementTarget="{Binding ElementName=Toggle}">
            <StackPanel>
                <TextBlock Foreground="White">
                    Enter  comment:
                </TextBlock>
                <TextBox Name="Comment"/>
            </StackPanel>
        </Popup>
    </StackPanel>
</Window>

using System;
using System.Windows;
using System.Windows.Data;


namespace ToggleButtonSpike
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();
        }
    }

    public class TextToBool : IValueConverter
    {
        #region IValueConverter Members

        public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
        {
            return !string.IsNullOrEmpty((string)value);
        }

        public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
        {
            throw new NotImplementedException();
        }

        #endregion
    }
}

Answer 3

单击切换按钮时。它会检查或取消选中，请记住。在第一次点击它时，它将被聚焦。请尝试：

<ToggleButton Focusable="False"/>

希望能帮到你

单击时ToggleButton不会取消选中

3 个答案: