我创建了一个SOAP调用,作为答案,我得到了一个XML字符串,如:
<?xml version="1.0" encoding="utf-8"?>
<sopenevelop>
<soapbody>
<ActualAnswer> I want to get whatever is in here </ActualAnswer>
</soapbody>
</sopenevelop>
那么如何从android中的那个xml中读出“ ActualAnswer ”?
我找到了这样的例子: XML String parsing in Android? 但它并没有真正说明如何过滤掉答案......并且无法使其正常运作..
在C#中我可以这样做,其中xmlanswer是顶部的xml,但无法在android中找到它
XmlDocument xml = new XmlDocument();
xml.LoadXml (xmlanswer);
string loginanswer = (xml.GetElementsByTagName ("ActualAnswer") [0].InnerText);
答案 0 :(得分:1)
过去,我创建了一个很好的类来加载和处理XML内容。
从资源文件夹加载的用法:
val rootTag=XmlTag.getXmlRootTagOfXmlFileResourceId(context,xmlResId)
或者,如果你在String实例中有它:
val rootTag=XmlTag.getXmlFromString(xmlString)
这里是代码:
/**
* an xml tag , includes its name, value and attributes
* @param tagName the name of the xml tag . for example : <a>b</a> . the name of the tag is "a"
*/
class XmlTag(val tagName: String) {
/** a hashmap of all of the tag attributes. example: <a c="d" e="f">b</a> . attributes: {{"c"="d"},{"e"="f"}} */
@JvmField
var tagAttributes: HashMap<String, String>? = null
/**list of inner text and xml tags*/
@JvmField
var innerTagsAndContent: ArrayList<Any>? = null
companion object {
@JvmStatic
fun getXmlFromString(input: String): XmlTag? {
val factory = XmlPullParserFactory.newInstance()
factory.isNamespaceAware = true
val xpp = factory.newPullParser()
xpp.setInput(StringReader(input))
return getXmlRootTagOfXmlPullParser(xpp)
}
@JvmStatic
fun getXmlRootTagOfXmlPullParser(xmlParser: XmlPullParser): XmlTag? {
var currentTag: XmlTag? = null
var rootTag: XmlTag? = null
val tagsStack = Stack<XmlTag>()
xmlParser.next()
var eventType = xmlParser.eventType
var doneParsing = false
while (eventType != XmlPullParser.END_DOCUMENT && !doneParsing) {
when (eventType) {
XmlPullParser.START_DOCUMENT -> {
}
XmlPullParser.START_TAG -> {
val xmlTagName = xmlParser.name
currentTag = XmlTag(xmlTagName)
if (tagsStack.isEmpty())
rootTag = currentTag
tagsStack.push(currentTag)
val numberOfAttributes = xmlParser.attributeCount
if (numberOfAttributes > 0) {
val attributes = HashMap<String, String>(numberOfAttributes)
for (i in 0 until numberOfAttributes) {
val attrName = xmlParser.getAttributeName(i)
val attrValue = xmlParser.getAttributeValue(i)
attributes[attrName] = attrValue
}
currentTag.tagAttributes = attributes
}
}
XmlPullParser.END_TAG -> {
currentTag = tagsStack.pop()
if (!tagsStack.isEmpty()) {
val parentTag = tagsStack.peek()
parentTag.addInnerXmlTag(currentTag)
currentTag = parentTag
} else
doneParsing = true
}
XmlPullParser.TEXT -> {
val innerText = xmlParser.text
if (currentTag != null)
currentTag.addInnerText(innerText)
}
}
eventType = xmlParser.next()
}
return rootTag
}
/**returns the root xml tag of the given xml resourceId , or null if not succeeded . */
fun getXmlRootTagOfXmlFileResourceId(context: Context, xmlFileResourceId: Int): XmlTag? {
val res = context.resources
val xmlParser = res.getXml(xmlFileResourceId)
return getXmlRootTagOfXmlPullParser(xmlParser)
}
}
private fun addInnerXmlTag(tag: XmlTag) {
if (innerTagsAndContent == null)
innerTagsAndContent = ArrayList()
innerTagsAndContent!!.add(tag)
}
private fun addInnerText(str: String) {
if (innerTagsAndContent == null)
innerTagsAndContent = ArrayList()
innerTagsAndContent!!.add(str)
}
/**formats the xmlTag back to its string format,including its inner tags */
override fun toString(): String {
val sb = StringBuilder()
sb.append("<").append(tagName)
val numberOfAttributes = if (tagAttributes != null) tagAttributes!!.size else 0
if (numberOfAttributes != 0)
for ((key, value) in tagAttributes!!)
sb.append(" ").append(key).append("=\"").append(value).append("\"")
val numberOfInnerContent = if (innerTagsAndContent != null) innerTagsAndContent!!.size else 0
if (numberOfInnerContent == 0)
sb.append("/>")
else {
sb.append(">")
for (innerItem in innerTagsAndContent!!)
sb.append(innerItem.toString())
sb.append("</").append(tagName).append(">")
}
return sb.toString()
}
}
答案 1 :(得分:0)
如果你想要使用jDom ......
http://www.mkyong.com/java/how-to-read-xml-file-in-java-jdom-example/
PS:无法在Linux上运行......
答案 2 :(得分:0)
SoapEnvelope result = (SoapEnvelope) envelope.getResponse();
Log.d("result : ", "" + result.toString());
String property_name= result.getProperty("ActualAnswer").toString();
或者你可以通过索引得到它,如下所示:
String property_name= result.getProperty(0).toString();
答案 3 :(得分:0)
尝试使用DOM
public static String checkLoginStatus(String response)
throws ParserConfigurationException, SAXException, IOException {
String status = "";
DocumentBuilder db = DocumentBuilderFactory.newInstance()
.newDocumentBuilder();
InputSource is = new InputSource();
Document doc = null;
is.setCharacterStream(new StringReader(response));
try {
doc = db.parse(is);
} catch (SAXException e) {
Log.d("Wrong XML file structure: ", e.getMessage());
e.printStackTrace();
throw e;
} catch (IOException e) {
Log.d("I/O exeption: ", e.getMessage());
e.printStackTrace();
throw e;
}
Node rootNode = doc.getElementsByTagName("soapbody").item(0);
Element rootElement = (Element) rootNode;
String status = getTagValue("ActualAnswer", rootElement);
Log.d("StatusCode", status);
return status;
}
public static String getTagValue(String sTag, Element eElement) {
NodeList nlList = eElement.getElementsByTagName(sTag).item(0)
.getChildNodes();
Node nValue = (Node) nlList.item(0);
if (nValue == null) {
return "";
} else {
return nValue.getNodeValue();
}
}