你可以在Java中转义变量吗?例如,在PHP中,我可以这样做:
$test = 3;
echo "He is {$test} years old";
将输出:
He is 3 years old
你能用Java做类似的事吗?
答案 0 :(得分:6)
您应该使用String.format
int age = 3;
String newString = String.format("He is %d years old", age);
%d - 说int。 %s - 用于字符串,%f用于float,以及越来越多的格式化选项。
你可以找到一个非常好的explenation here:
诺姆。
答案 1 :(得分:2)
我认为你需要这种方式
Int x=3;
String test="He is "+x+"years old";
System.out.println(test);
output
He is 3 years old
答案 2 :(得分:0)
我可能误解了这个问题,但我会这样做
Public Sub acToxlRecordsets()
Dim xlApp As Object, xlwkb As Object
Dim db As Database
Dim rst As Recordset
Dim args As Collection, arg As Variant
Dim strPath As String, strSQL As String
Dim i As Integer
Dim fld As Field
' INITIALIZE OBJECTS
Set db = CurrentDb()
Set xlApp = CreateObject("Excel.Application")
args.Add ("arg1")
args.Add ("arg2")
args.Add ("arg3")
strPath = "C:\Path\To\Excel\Files"
i = 1
For Each arg In args
' CREATE NEW WORKBOOK
Set xlwkb = xlApp.Workbooks.Open(strPath & "\ExcelFile" & i)
' OPEN NEW RECORDSET
strSQL = "select * from myQuery where arguments = " & arg
Set rst = db.OpenRecordset(strSQL, dbOpenDynaset)
rst.MoveFirst
' OUTPUT RECORDSET
' FIRST COLUMNS
xlwkb.Worksheets(1).Activate
xlwkb.Worksheets(1).Range("A1").Select
For Each fld In rst.Fields
xlApp.ActiveCell = fld.Name
xlApp.ActiveCell.Offset(0, 1).Select
Next
' NEXT ROWS
xlwkb.Worksheets(1).Range("A2").CopyFromRecordset rst
xlwkb.Worksheets(1).Range("A1").Select
' SAVE AND CLOSE EXCEL WORKBOOK
xlwkb.Close True
i = i + 1
Next arg
' UNINITIALIZE OBJECTS
rst.Close
Set xlwkb = Nothing
Set xlApp = Nothing
Set rst = Nothing
Set db = Nothing
End Sub