Question

我认为如果我只是逐字地解答您的问题，这是最简单的：

“编写一个python程序，不断向用户询问10以外的数字。如果输入10，则谴责用户他们不要猜数字10”。

我收到错误 - 基本上，我不知道在进入while循环之前如何定义guess变量。

target, guess = 10

while target != guess:
    guess = int(input('Enter a number other than 10: '))

print("Hey, you weren't supposed to enter 10!")

Answer 1

您可以将元组分配给这样的元组

target, guess = 10, 10

你实际上并不希望它们是相同的，因为while循环立即退出。

你可以说

target, guess = 10, None

但通常用两行来写这个更清楚

target = 10
guess = None

另一种方法是避免在第一时间分配一个虚拟值来猜测

target = 10
while True:
    guess = int(input('Enter a number other than 10: '))
    if guess == target:
        break

print('Hey, you werent supposed to enter 10!')

Answer 2

创建该错误是因为您尝试将两个变量分配给一个事物（整数10）。如果您希望两个变量都等于10，则需要执行以下操作：

target = guess = 10

但是，在此程序中，您不需要该功能。相反，你会想要这样的东西：

# Set target equal to 10
target = 10
# Make guess equal None, since there are no guesses yet
guess = None

# Loop until guess equals target
while target != guess:
    # Get new guess
    guess = int(input('Enter a number other than 10: '))

# Print message
print('Hey, you werent supposed to enter 10!')

Answer 3

只需创建一个变量＆＃34; num＆＃34;价值不是10（我已经拿了11）然后创建一个局部变量作为num并输入你喜欢的值，你将获得结果

num=11
while num!=10:
      num=int(input("Enter a number other than 10"))
print "I thought i said no to 10"

Answer 4

你可以这样做......

condition = True

while condition == True:
  number = int(input("Enter a number"))
  if number == 10:
     print("You can't enter ten") #or whatever you want to say
  else:
    condition = False #if you want to drop out of the loop

希望这有助于：）

Easy Python：数字Guesser

4 个答案: