我正在尝试Simple XML serializer。我对XML-> Java中的反序列化更感兴趣。这是我的代码作为单元测试:
import java.io.StringReader;
import java.io.StringWriter;
import junit.framework.TestCase;
import org.simpleframework.xml.Attribute;
import org.simpleframework.xml.Root;
import org.simpleframework.xml.Serializer;
import org.simpleframework.xml.core.Persister;
public class SimpleTest extends TestCase {
public void testWriting() throws Exception {
StringWriter writer = new StringWriter();
Address address = new Address("1234 Main Street", "San Francisco", "CA");
Serializer serializer = new Persister();
serializer.write(address, writer);
System.out.println("Wrote: " + writer.getBuffer());
}
public void testReading() throws Exception {
String input = "<address street='1234 Main Street' city='San Francisco' state='CA'/>";
Serializer serializer = new Persister();
System.out.println("Read back: " + serializer.read(Address.class, new StringReader(input)));
}
}
@Root
class Address {
@Attribute(name="street")
private final String street;
@Attribute(name="city")
private final String city;
@Attribute(name="state")
private final String state;
public Address(@Attribute(name="street") String street, @Attribute(name="city") String city, @Attribute(name="state") String state) {
super();
this.street = street;
this.city = city;
this.state = state;
}
@Override
public String toString() {
return "Address [city=" + city + ", state=" + state + ", street=" + street + "]";
}
}
这样可行,但Address类中重复的@Attribute
注释(在字段和构造函数参数中)看起来很难看。有没有办法:
答案 0 :(得分:1)
我认为你不需要所有的重复和额外的注释属性。如果名称与object属性相同,则默认使用它。
所以您可以将其声明为:
@Root
class Address {
@Attribute
private final String street;
@Attribute
private final String city;
@Attribute
private final String state;
public Address(String street, String city, String state) {
super();
this.street = street;
this.city = city;
this.state = state;
}
@Override
public String toString() {
return "Address [city=" + city + ", state=" + state + ", street=" + street + "]";
}
}
答案 1 :(得分:0)
如果Java实现Serializable
并遵守JavaBean语法,Java将默认序列化所有类成员。
答案 2 :(得分:0)
我有类似的担忧,但有相当复杂的对象结构。 我通过使用JAXB库进行编组和解编来解决这个问题,这是一个非常常见的问题。 您还可以考虑通过使用方面将编组逻辑与java类完全分离 - 您可以在单独的方面处理所有注释,这将使您的java类完全清除编组注释。