Question

我正在尝试创建一个PBBG应用程序。（其中pbbg代表持久的基于浏览器的游戏）

因为我需要为每个服务器配置多个服务器db。

为了将数据写入从属数据库，我只需将int value保存到静态属性中，例如：

    public static function allocate_new_village() {
        VillageSlaveM::$server_id = Yii::app()->session['user_active_world'];//1,2,3,4,5,...
        $model_village_slave_m = new VillageSlaveM();
        $model_village_slave_m->x = 1;
        $model_village_slave_m->y = 1;
        $model_village_slave_m->k = 1;
        $model_village_slave_m->name = 'standard';
        $model_village_slave_m->user_id = 1;
        if ($model_village_slave_m->validate() && $model_village_slave_m->save()) {
//            echo 1;
        } else {
//            echo 2;
        }
    }

以下示例使用主db：

创建CActivedataProvider

$dataProvider = new CActiveDataProvider('Village');
        $this->render('index', array(
            'dataProvider' => $dataProvider,
        ));

如何使用从属数据库和CActiveDataProvider模型创建VillageSlaveM？

<?php

class VillageSlaveM extends Village {

    public static function model($className = __CLASS__) {
        return parent::model($className);
    }

    public static $server_id = 1;
    public static $master_db;

    public function getDbConnection() {
        //echo __FUNCTION__;
        //die;
        //echo 111;
        self::$master_db = Yii::app()->{"db" . self::$server_id};
        if (self::$master_db instanceof CDbConnection) {
            self::$master_db->setActive(true);
            return self::$master_db;
        }
        else
            throw new CDbException(Yii::t('yii', 'Active Record requires a "db" CDbConnection application component.'));
    }

}

Answer 1

出于某种原因，起初它没有用，现在确实如此：

VillageSlaveM::$server_id = Yii::app()->session['user_active_world'];
$dataProvider = new CActiveDataProvider('VillageSlaveM');
$this->render('index', array(
    'dataProvider' => $dataProvider,
));

如何在使用多个数据库时从从模型创建CActiveDataProvider

1 个答案: