Question

我似乎无法通过此查询向我提供正确的结果。

select 
    datepart(day, i.timestamp) as [day], 
    i.campaignID, i.creativeID
    , count(distinct i.sessionID) as [Impressions]
    , count(case when e.eventID in (1,2,3) then 1 else 0 end) as Clicks

from impressions i 
left join Events e 
    on i.sessionID = e.sessionID

group by 
    datepart(day, i.timestamp)
    , i.campaignID, i.creative

order by [day]

我也尝试在then子句中用e.eventid替换1。我在结果中获得了太多的点击。事件每个sessionid有多个记录，因为许多类型的事件可以在同一个会话中发生（翻转，滚动等）我想要计算的事件将具有1,2或3的偶数，因为这些将是3您可以点击的可能链接。我想要的是通过获得点击次数和相关点击来计算点击率，如果没有点击我希望它反映为0而不是从结果中丢失，这就是我得到的。

任何帮助表示感谢，提前感谢您的宝贵时间！

Answer 1

尝试将第二个count替换为sum，如下所示：

select 
  datepart(day, i.timestamp) as [day], 
  i.campaignID, i.creativeID
  , count(distinct i.sessionID) as [Impressions]
  , sum(case when e.eventID in (1,2,3) then 1 else 0 end) as Clicks

from impressions i 
left join Events e 
  on i.sessionID = e.sessionID

group by 
  datepart(day, i.timestamp)
  , i.campaignID, i.creative

order by [day]

或者，您可以保留count并将eventID过滤转移到where子句：

select 
  datepart(day, i.timestamp) as [day], 
  i.campaignID, i.creativeID
  , count(distinct i.sessionID) as [Impressions]
  , count(e.eventID) as Clicks

from impressions i 
left join Events e 
  on i.sessionID = e.sessionID

where e.eventID in (1,2,3)

group by 
  datepart(day, i.timestamp)
  , i.campaignID, i.creative

order by [day]

但我怀疑你的on子句中需要额外的过滤条件。但是，我不知道你的桌子的结构是肯定的。

查询以获取展示次数和相关点击次数

1 个答案: