Question

我从HTTPPOST获得响应，从中获取一个子字符串，即URL，然后在其上执行HTTPGET，我无法获得任何响应。有关问题的任何意见？

 String pkmspogout1 = result.substring(result.indexOf(",")+1,result.length());
                        Log.i("Lpkmspogout1 ", pkmspogout1);


                    HttpClient httpclient4 = new DefaultHttpClient();

                    HttpResponse logoutresponse  ;
                    try {
                        HttpGet httpget = new HttpGet(pkmspogout1);

                        logoutresponse = httpclient4.execute(httpget);
                        BufferedReader in2 = new BufferedReader(new InputStreamReader(logoutresponse.getEntity().getContent()));

                        StringBuffer sb2 = new StringBuffer("");

                        String line2 = "";
                        String NL2 = System.getProperty("line.separator");
                         while ((line2 = in2.readLine()) != null) {
                            sb2.append(line + NL2);

                        }
                        in2.close();


                        String pkmslogout5 = sb2.toString();
                        Log.i("logoutresponse from pkms", pkmslogout5+"");
                    } catch (Exception e) {}

Answer 1

pkmspogout1 是否是正确的网址？此外，您应该确保执行以下操作以查看任何错误：

catch (Exception e) {e.printStackTrace();}

尝试按如下方式对网址进行编码：

String[] url = pkmspogout1.split("com"); //Or whatever is the last part of the main url. 
                         //The letter "." means any character btw as it is a regular expression.
String finalUrl = url[0];
for(int i=0; i<url.length; i++){
     finalUrl += URLEncoder.encode(url[i],"UTF-8");
}

说实话有点粗糙......为什么在服务器端形成时会更好地编码呢。

你可以尝试：

pkmspogout1 = pkmspogout1.replace("http://","");
pkmspogout1 = URLEncoder.encode(pkmspogout1);
pkmspogout1 = "http://"+pkmspogout1;

查看是否只是“http：//”破坏了您的网址。我仍然认为这是最重要的问题，因为你告诉我硬编码它的工作正常。

Answer 2

终于工作了，Phew！我试过（pkmspogout1.trim（））并且它有效！（URL之前和之后的空格是问题）。

异步任务中的HTTP GET不起作用

2 个答案: