Question

新手程序员在这里。我正在使用Java来尝试创建一个数字猜谜游戏。我希望我的do while循环继续循环，直到用户输入正确的数字或者他们用完了猜测。这就是我所拥有的，我无法弄清楚如何在我的生命中使用2个布尔控制器。

do
    {System.out.println("Enter guess #1");
    userGuess = keyboard.nextInt();

    } while ((userGuess != actualNumber) || (remainingGuesses = guesses;       remainingGuesses >= 1; remainingGuesses--));

感谢任何帮助！

Answer 1

我认为你想要更接近这种效果：

remainingGuess = guesses;
do {
   System.out.println("Enter guess #1");
   userGuess = keyboard.nextInt();
} while ( userGuess != actualNumber || remainingGuesses-- > 0 )

逐行：

remainingGuesses = guesses;

将guesses分配给remainingGuesses 一次，如果您在循环的每次迭代中都这样做，它就永远不会结束

userGuess != actualNumber || remainingGuesses-- > 0

在用户猜错时继续进行迭代或 remainingGuesses超过0。

remainingGuesses--

计算变量remainingGuesses的当前值，然后在表达式递减1之后。

Answer 2

在进入循环之前初始化剩余的猜测。仅检查while“paranthesis”（）中的条件

reaminingGuesses = guesses;
do
    {System.out.println("Enter guess #1");
    userGuess = keyboard.nextInt();
    remainingGuess--;
    } while ((userGuess != actualNumber) || (remainingGuesses >= 1));

Answer 3

如果你想要它，我会做一些小的改动，并假设你有像regularNumber和允许的猜测总数定义的常量：

// break the calls into seperate methods, to make them easier to read in the long term and to 
// seperate logical concerns into discrete elements.
do {
//  get the user guess
   guess = getGuess();
// if shouldStop returns true you would stop, if it returns false you should continue, thus the !..
}  while (!shouldStop(guess)) {
   // decrement the guesses.
   --remainingGuesses;
}

///  define these methods somewhere..,
// get your guess
public int getGuess() {
   System.out.println("Enter guess #1");
   return keyboard.nextInt();
}


public boolean shouldStop(int guess) {
// condensed if statement syntax in java, very handy for this kind of thing
    // do we have enough remaining guess to keep going?  If so, compare the guess to the actual number
   // otherwise return true (the stop signal
   return remainingGuesses > 0 ? guess == actualNumber : true;
}

如果你真的想要完成整个过程，你可以将guess ==实际数字分解为一个方法，但在这种情况下可能不需要它，因为它是一个简单的相等检查。

可以通过多种方式定义方法shouldStop ......

在早期，我认为完全编写这些逻辑块并从那里压缩是有帮助的，例如：

public boolean shouldStop(int guess) {
  if(remainingGuesses <=0) {
     return true;
  }  else if(guess == actualNumber) {
     return true;
  }  else {
     return false;
}

}

将2个布尔控制器放入do while表达式中？

3 个答案: