我正在尝试将我用Python制作的游戏移植到Java。在Python版本中,我将所有方法和变量放在一个“类”中,并且播放器是这样的字典:
game.py
...
new_player={"name":"","hp":0,...}
players=[]
//to add new player
players.append(new_player.copy())
然后单独添加玩家的数据值:
...
players[0]["name"]="bob"
players[0]["hp"]=50
...
在Java版本中,我有一个单独的类用于定义Player对象,以及游戏的主要方法。
例如(这是一个小版本):
game.java(返回省略)
import java.utils.*;
public class game
{
public static ArrayList<player> players = new ArrayList<player>();
public static ArrayList<String> pdead = new ArrayList<String>();
public static int turn = 0;
public static void main(String[] args)
{
//do stuff
players.add(new player(name));
//do other stuff
}
public static void do_move(move)
{
//some move is selected
players.get(turn).set_hp(10);
//at this point compiler throws error: cannot find symbol
//compiler does not recognize that a player should have
//been added to the players variable
//other stuff
};
};
player.java(返回省略)
public class player
{
//arbitrary list of private variables like hp and name
public player(new_name)
{
name = new_name;
//other variables defined
};
public void set_hp(int amount) //Adding hp
{
hp += amount;
};
public void set_hp(int amount,String type) //taking damage
{
mana += amount;
//go through types, armor, etc.
hp -= amount;
};
public void display stats() //displays all player's stats before choosing move
{
//display stats until...
//later in some for loop
System.out.println(players.get(index).get_hp());
//here compiler throws error again: cannot find symbol
//players arraylist is in main class's public variables
//other stuff
};
//other stuff
};
据说,当两个要编译的类一起编译时,程序将能够运行,因为主变量是公共的,并且随着程序的继续定义了播放器变量。但是,编译器无法识别并抛出错误,因为类(在同一目录中,顺便说一下)不会相互读取,并且在检查时数组/ arraylist中没有“定义”对象。
如何让编译器看到变量?如果需要,我可以上传这两个类的当前工作版本和最终的python版本,但我喜欢让我的游戏保持封闭源代码。
编辑:根据sjkm的回复修复ArrayList初始化
答案 0 :(得分:0)
定义列表的通用类型:
变化
public static ArrayList players = new ArrayList<player>();
public static ArrayList pdead = new ArrayList<String>();
到
public static ArrayList<player> players = new ArrayList<player>();
public static ArrayList<String> pdead = new ArrayList<String>();
否则你总是要从列表中投射出来的对象......