我想使用这个脚本...但是由于关键约束,它不会让我放弃表...任何想法?
CREATE DATABASE IF NOT EXISTS DATABASEONE;
USE DATABASEONE;
DROP TABLE IF EXISTS st_glowne_st_pages;
CREATE TABLE `st_glowne_st_pages` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`fk_glowne` varchar(50) COLLATE utf8_polish_ci NOT NULL,
`fk_pages` varchar(50) COLLATE utf8_polish_ci NOT NULL,
`kolejnosc` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `id` (`id`),
KEY `fk_glowne` (`fk_glowne`),
KEY `fk_pages` (`fk_pages`),
CONSTRAINT `st_glowne_st_pages_ibfk_1` FOREIGN KEY (`fk_glowne`) REFERENCES `st_glowne` (`name`) ON DELETE CASCADE ON UPDATE CASCADE,
CONSTRAINT `st_glowne_st_pages_ibfk_2` FOREIGN KEY (`fk_pages`) REFERENCES `st_pages` (`name`)
) ENGINE=InnoDB AUTO_INCREMENT=9 DEFAULT CHARSET=utf8 COLLATE=utf8_polish_ci;
INSERT INTO st_glowne_st_pages VALUES("1","admin.php","pageadmin.php","1");
INSERT INTO st_glowne_st_pages VALUES("3","index.php","pageindex.php","1");
INSERT INTO st_glowne_st_pages VALUES("4","work.php","pagework.php","1");
INSERT INTO st_glowne_st_pages VALUES("7","register.php","pageregister.php","1");
INSERT INTO st_glowne_st_pages VALUES("8","login.php","pagelogin.php","1");
答案 0 :(得分:0)
DO
SET FOREIGN_KEY_CHECKS = 0;
...drop code...
SET FOREIGN_KEY_CHECKS = 1;