Question

我在main（）方法中有两个独立的拓扑。我正在使用'for loop'来设置相应的喷口和螺栓并提交该拓扑结构。每个拓扑结构都有一组独立的喷口和螺栓，其中包含不同的逻辑。

现在我想动态调用不同的喷口和螺栓。我怎么能这样做？

主方法中的

代码：

    public static void main(String[] args) throws InterruptedException,Exception            
    {
    LocalCluster cluster = new LocalCluster();



    try{
        BufferedReader in=new BufferedReader(new FileReader("/home/praveen /workspace/OfferEngine/OfferListJSON.json"));
        //ArrayList<String> content = new ArrayList<String>();
        String str="";
        String str1="";
        while((str1=in.readLine())!=null)
        {
            str = str + str1;
        }

         JsonParser parser = new JsonParser();
         JsonObject o = (JsonObject)parser.parse(str);
         JsonObject o2 = (JsonObject)o.get("OfferData");

         ArrayList<String> ol = new ArrayList<String>();
         ol.add(o2.get("strOfferId").toString().replaceAll("^\"|\"$", ""));
         ol.add(o2.get("strOfferId1").toString().replaceAll("^\"|\"$", ""));

         TopologyBuilder bu = null;
         Config config = new Config();
         config.setDebug(false);

         for(String x : ol) {
                System.out.println(x); //prints element x
                String y="", z="";
                bu = new TopologyBuilder();         
                bu.setSpout(x, new Off1Spout(x).ks(), 2);
                y = x+"2";
                bu.setBolt(y, new main.java.bolts.Off1Bolt()).shuffleGrouping(x);
                z = x+"offerlimit";
                bu.setBolt(z, new OfferLimit()).shuffleGrouping(y);
cluster.submitTopology(x,config,bu.createTopology());
              }
    }

    catch (IOException e) 
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

任何建议都更有帮助...谢谢你们

Answer 1

您可以在for循环内尝试不同商品的if（）条件...请参阅以下代码供您参考

for(String x : ol) {
     System.out.println(x); 
//  Offer 1 related Topology
    if(x.equalsIgnoreCase("offer1")){                   
       String y="", z="";
       bu = new TopologyBuilder();          
       bu.setSpout();
       y = x+"start";
       cluster.submitTopology(x,config,bu.createTopology());
    }

//      Offer 2 related Topology

 if(x.equalsIgnoreCase("off2")){

       String y="", z="";
       bu = new TopologyBuilder();          
       bu.setSpout(x, new Off1Spout(x).ks(), 2);
       y = x+"start";
       bu.setBolt(y, new off2Bolt()).shuffleGrouping(x);
       cluster.submitTopology(x,config,bu.createTopology());
  }
}

有多少拓扑创造了许多条件..

在本地模式下运行多个风暴拓扑

1 个答案: