Question

我有这个

import random 

a = random.randint(1,100) 
b = random.randint(1,100) 
c = random.randint(1,100) 
d = random.randint(1,100) 
e = random.randint(1,100) 

print "The numbers are a:",a,"b:",b,"c:",c,"d:",d,"and e:",e 
print "The numbers in ascending order:" 
list1=[a,b,c,d,e]
list1.sort(key=int)
print a
print b
print c
print d
print e`

但是我无法理解我想要打印新值而不是旧值...

Answer 1

遍历list1并打印每个值：

for number in list1:
    print number

Answer 2

对列表进行排序时，您分配的原始变量不会更改，只会更改列表的内容。

您可以从排序列表中重新分配变量：

list1=[a,b,c,d,e]
list1.sort(key=int)
a, b, c, d, e = list1

print a
print b
print c
print d
print e

Answer 3

您将变量的数量放入列表list1。如果您对列表进行排序，则不会将a的值更改为e。

如果你想打印它们，在列表上排序并打印所有元素，然后对它们进行排序。

for current in list1:
    print current

Answer 4

这有效

import random 

a = random.randint(1,100) 
b = random.randint(1,100) 
c = random.randint(1,100) 
d = random.randint(1,100) 
e = random.randint(1,100) 

print "The numbers are a:",a,"b:",b,"c:",c,"d:",d,"and e:",e 
print "The numbers in ascending order:" 
list1=[a,b,c,d,e]
list1.sort(key=int)

for item in list1:
    print item

Answer 5

import random 

a = random.randint(1,100) 
b = random.randint(1,100) 
c = random.randint(1,100) 
d = random.randint(1,100) 
e = random.randint(1,100) 

print "The numbers are a:",a,"b:",b,"c:",c,"d:",d,"and e:",e 
print "The numbers in ascending order:" 
list1=[a,b,c,d,e]
list1.sort(key=int)
for item in list1:
    print(str(item) + '\n')

你的观念有问题。是的，a，b，c，d，e是由random.randint（）创建的。对list1进行排序时，list1的更改不会更改a,b,c,d,e。因为在list1中，只有从a,b,c,d,e内部复制的值，而不是a,b,c,d,e本身。因此，您无法通过更改list1来更改a，b，c，d，e的值。

Answer 6

通过创建和排序list1，您可以更改列表的内容，而不是实际变量a，b，c，d和e。如果你想让python打印“新值”，你必须打印list1。

import random 

a = random.randint(1,100) 
b = random.randint(1,100) 
c = random.randint(1,100) 
d = random.randint(1,100) 
e = random.randint(1,100) 

print "The numbers are a:",a,"b:",b,"c:",c,"d:",d,"and e:",e 
print "The numbers in ascending order:" 
list1=[a,b,c,d,e]
list1.sort(key=int)

for num in list1:
    print num

Python列出并排序随机生成的数字

6 个答案: