Question

我正在尝试选择具有MAX微博计数的用户：

SELECT "name", count(*) FROM "users" 
  INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id"
  GROUP BY users.id

然后返回

"Delphia Gleichner";15
"Louvenia Bednar IV";10
"Example User";53
"Guadalupe Volkman";20
"Isabella Harvey";30
"Madeline Franecki II";40

但我想只选择"Example User";53，（具有MAX微博计数的用户）

我尝试添加HAVING MAX(count*)，但这不起作用。

Answer 1

我尝试使用ORDER BY max DESC LIMIT 1，其中maximum是count（*）字段。类似的东西：

SELECT "name", count(*) maximum FROM "users" 
   INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id 
ORDER BY maximum DESC 
LIMIT 1

我现在没有mysql可用，所以我在纸上做这个（它可能不起作用），但它只是一个方向。

Answer 2

SELECT x.name, MAX(x.count)
FROM (
 SELECT "name", count(*)
  FROM "users" INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id"
  GROUP BY users.id
) x

Answer 3

也许是这样的：

SELECT "name", count(*) 
FROM "users" 
INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id
HAVING COUNT(microposts) = (SELECT COUNT(microposts) 
                         FROM   users
                         GROUP  BY microposts
                         ORDER  BY COUNT(microposts) DESC 
                         LIMIT  1)

没有测试，但它可能有效

Answer 4

SELECT TOP 1 "name", count(*) AS ItemCount FROM "users" 
INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id" 
GROUP BY users.id
ORDER BY ItemCount DESC

Answer 5

这很简单，你可以尝试：

SELECT "name", MAX(count_num) FROM 
(SELECT "name", count(*) as count_num
FROM "users" INNER JOIN "microposts" ON "microposts"."user_id" = "users"."id"
GROUP BY users.id) x

SQL select MAX（COUNT）

5 个答案: