Question

人。我有查询，它计算每一天的一些事件的数量。但它以错误的格式返回日期。

select trunc(action_dt) as action_dt, count(*) as cnt
from stat.jurnal_orders
where action_dt between TO_DATE('17.05.12','DD/MM/YY') AND TO_DATE('12.11.13','DD/MM/YY')
group by trunc(action_dt)
order by action_dt asc

在数据库中，我的日期在DD.MM.YYYY，但我想要YYYY / MM / DD 有人可以帮我解决这个问题吗？

Answer 1

你有两个选择

首先 - 使用TO_CHAR

在查询中明确设置所需的格式

select to_char(trunc(action_dt),'yyyy/mm/dd') as action_dt, count(*) as cnt
from stat.jurnal_orders
where action_dt between TO_DATE('17.05.12','DD/MM/YY') AND TO_DATE('12.11.13','DD/MM/YY')
group by to_char(trunc(action_dt),'yyyy/mm/dd')
order by action_dt asc

其次，在会话级别设置nls_date_format。

alter session set nls_date_format = 'yyyy/mm/dd';

并查询

select trunc(action_dt) as action_dt, count(*) as cnt
    from stat.jurnal_orders
    where action_dt between TO_DATE('2012/05/17') AND TO_DATE('2013/12/11')
    group by trunc(action_dt)
    order by action_dt asc

Answer 2

要将日期转换为其他格式，您可以使用Oracle TO_CHAR函数。 http://www.techonthenet.com/oracle/functions/to_char.php

对于您的示例，假设您想首先TRUNC日期，您可以像这样使用它：

SELECT TO_CHAR(TRUNC(action_dt), 'YYYY/MM/DD') as action_dt
FROM some_table

Answer 3

请尝试TO_CHAR：

select TO_CHAR (sysdate, 'YYYY/MM/DD') from dual;

Answer 4

SELECT REPLACE(CONVERT(VARCHAR(10), action_dt, 102), '.', '/')

http://msdn.microsoft.com/en-us/library/ms187928.aspx

编辑：这是针对T-SQL而不是Oracle。误读了这个问题。

日期格式正确

4 个答案: