Question

请不要将此问题报告为重复，因为现有的解决方案都没有为我工作，我对它们进行了全部测试

所以，我试图在我的RaspberryPi模型B板上运行PyAudio示例录制程序，这是我得到的错误，

Traceback (most recent call last):
  File "/home/pi/pyaudio/test/testing.py", line 23, in <module>
    data = stream.read(chunk)
  File "/usr/local/lib/python2.7/dist-packages/pyaudio.py", line 605, in read
    return pa.read_stream(self._stream, num_frames)
IOError: [Errno Input overflowed] -9981

已经有某些解决方案可以解决许多用户的问题，在我看来，这是不正确的。

这是我尝试过的，

首先，这是代码，

"""PyAudio example: Record a few seconds of audio and save to a WAVE file."""

import pyaudio
import wave

CHUNK = 1024
FORMAT = pyaudio.paInt16
CHANNELS = 1
RATE = 44100
RECORD_SECONDS = 5
WAVE_OUTPUT_FILENAME = "output.wav"

p = pyaudio.PyAudio()

stream = p.open(format=FORMAT,
            channels=CHANNELS,
            rate=RATE,
            input=True,
            frames_per_buffer=CHUNK)

print("* recording")

frames = []

for i in range(0, int(RATE / CHUNK * RECORD_SECONDS)):
   data = stream.read(CHUNK)
   frames.append(data)

print("* done recording")

stream.stop_stream()
stream.close()
p.terminate()

wf = wave.open(WAVE_OUTPUT_FILENAME, 'wb')
wf.setnchannels(CHANNELS)
wf.setsampwidth(p.get_sample_size(FORMAT))
wf.setframerate(RATE)
wf.writeframes(b''.join(frames))
wf.close()

如果支持或不支持当前配置，我也尝试过，

import pyaudio
p = pyaudio.PyAudio()
if p.is_format_supported(48000.0, 
    input_device=1,
    input_channels=1,
    input_format=pyaudio.paInt16):
    print 'True!'

44,000和44,100都是支持，但我仍然一次又一次地得到同样的错误。

这是我的USB声卡设备信息，

p.get_device_info_by_index(1)

{'defaultSampleRate': 44100.0, 
'defaultLowOutputLatency': 0.011609977324263039, 
'defaultLowInputLatency': 0.011609977324263039, 
'maxInputChannels': 1L, 
'structVersion': 2L, 
'hostApi': 0L, 
'index': 1, 
'defaultHighOutputLatency': 0.046439909297052155, 
'maxOutputChannels': 2L, 
'name': u'Generic USB Audio Device: USB Audio (hw:1,0)', 
'defaultHighInputLatency': 0.046439909297052155}

有没有人知道我为什么还会收到错误？

Answer 1

将您的chunk参数更改为8192而不是1024.为我工作。参考：IOError: [Errno Input overflowed] -9981

Answer 2

Did you try setting exception_on_overflow to False? From the Pyaudio documentation:

read(num_frames, exception_on_overflow=True)

Read samples from the stream. Do not call when using non-blocking mode.

Parameters: num_frames – The number of frames to read. exception_on_overflow – Specifies whether an IOError exception should be thrown (or silently ignored) on input buffer overflow. Defaults to True. Raises IOError: if stream is not an input stream or if the read operation was unsuccessful. Return type:
string

Answer 3

# importing modules for sound handling
# importing modules for sound handling
from sys import byteorder
from array import array
from struct import pack

import pyaudio
import wave

def audioeffect():
    CHUNK = 16 # played with, this can be 2048 1024, 512, 256 etc
    FORMAT = pyaudio.paInt16
    CHANNELS = 1
    RATE = 48000

    p = pyaudio.PyAudio()

    stream = p.open(format=FORMAT,
                channels=CHANNELS,
                rate=RATE,
                input=True,
                output=True,
                frames_per_buffer=CHUNK)
    r = array('h') # define r
    snd_data = array('h', stream.read(CHUNK)) # read sounddata from input
    r.extend(snd_data)
    stream.stop_stream()
    stream.close()
    p.terminate()
    N = 1
    SumOfSquars = 0
    for i in snd_data:  # determing the value for tel of  
        N = N +1

    # adding all quadrates
    for i in range(0, N-1):
        SumOfSquars = snd_data[i]**2
    Rms_Value = np.sqrt(SumOfSquars / N)

    #print("Rms_Value is  :", Rms_Value)
    return int(Rms_Value)

Answer 4

我刚刚增加了块数，看起来它有效！这是我的代码

import pyaudio
import wave

CHUNK = 44100  #just a big number
FORMAT = pyaudio.paInt16
CHANNELS = 1 #i found that my mic has 1 channel
RATE = 44100
RECORD_SECONDS = 5
WAVE_OUTPUT_FILENAME = "output.wav"

p = pyaudio.PyAudio()

stream = p.open(format=FORMAT,
                channels=CHANNELS,
                rate=RATE,
                input_device_index=3, #found that also
                input=True,
                frames_per_buffer=CHUNK)

print("* recording")

frames = []

for i in range(0, int(RATE / CHUNK * RECORD_SECONDS)):
    data = stream.read(CHUNK)
    frames.append(data)

print("* done recording")

stream.stop_stream()
stream.close()
p.terminate()

wf = wave.open(WAVE_OUTPUT_FILENAME, 'wb')
wf.setnchannels(CHANNELS)
wf.setsampwidth(p.get_sample_size(FORMAT))
wf.setframerate(RATE)
wf.writeframes(b''.join(frames))
wf.close()

Answer 5

详细说明@Sidd Rajput的答案，因为我没有清楚地指出这一点，如果要导入，仅在脚本/项目中进行设置是不够的-pyaudio.py本身需要修改

def read(self, num_frames, exception_on_overflow=False):

^ pyaudio.py v0.2.8中的589/590行：

PyAudio输入溢出-9981 - 没有解决方案正常工作

5 个答案: