Question

import java.util.Scanner;

public class diamond {
    public static void main (String[] args){

        Scanner scan = new Scanner(System.in);

        System.out.println("Please enter an integer");
        int lines = scan.nextInt();

        for(int counter = 1; counter <= lines; counter++)
        {   
            if (counter%2 != 0)
            {
                for(int count2 = 1; count2 <= counter; count2++){
                System.out.print("*");
                }
            System.out.println();
            }
        }
    }
}

我应该向用户询问一些行并输出一个由星号组成的钻石。我需要一些帮助来弄清楚如何使星号居中。我知道对于字符串有一些String.utils方法或其他东西，但输出是基于for循环的碎片，所以我不认为这真的有效。如果确实如此，请务必告诉我。

Answer 1

您需要在每行之前打印一定量的空格。然后，你需要另一个for循环反之。试试这段代码：

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);

    System.out.println("Please enter an integer ");
    int lines = scan.nextInt();

    for (int counter = 1; counter <= lines; counter++) {

        if (counter % 2 != 0) {
            for (int i = 0; i < lines - (counter / 2) - 3; i++) {
                System.out.print(" ");
            }
            for (int count2 = 1; count2 <= counter; count2++) {
                System.out.print("*");
            }
            System.out.println();
        }
    }
    for (int counter = lines - 1; counter >= 1; counter--) {

        if (counter % 2 != 0) {
            for (int i = 0; i < lines - (counter / 2) - 3; i++) {
                System.out.print(" ");
            }
            for (int count2 = 1; count2 <= counter; count2++) {
                System.out.print("*");
            }
            System.out.println();
        }
    }
}

Answer 2

我认为你应该准备一个字符串在每一行打印出来，然后你会知道它有多少个字符，当行增加时，删除字符串中心的两个'*'并添加一个“”在它前面，然后再打印出来。

需要帮助集中文本输出

2 个答案: