参考我以前的问题can only concatenate tuple (not "unicode") to tuple
现在,当我在媒体文件的网址上尝试 GET请求时,我收到以下错误。
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/media/media/abyss.jpg
Urls.py
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls)),
url(r'^$', 'blog.views.index'),
url(r'^blog/(?P<slug>[\w\-]+)/$', 'blog.views.article'),
url(r'^(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}),
)
答案 0 :(得分:0)
我遇到了同样的问题,这就是我要解决的问题: 我的项目结构
./django_site
app1/
app2/
media/
django_site/
settings.py
#your other basic config stuff in here
在settings.py中:
MEDIA_ROOT = os.path.join(os.path.dirname(os.path.dirname(os.path.abspath(__file__))), 'media')
MEDIA_URL = '/media/'
在子目录django_site /
中的urls.py中#the main url patterns
urlpatterns = patterns('',
#urls
)
"""Here's where we're putting the route to serve media from MEDIA_URL.
I couldn't get this part to work inside the inital declaration of urlpatterns.
Maybe you'll have better luck """
urlpatterns += patterns('',
(r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}))
然后在模板中:
<img src="{{ MEDIA_URL }}{{ image_name }}" height="200" width="400"/>
我从基于函数的视图传递image_name
。如图所示,您必须在某个时刻定义http://somesite.com/media/
网址,以便能够从MEDIA_URL
提取媒体。我没有在文档中明确地看到这一点,但是,除非配置url路由,否则GET请求似乎总是失败。现在,我从模板中或直接通过url拉取文件。希望这有帮助!