我整晚都在尝试这个,但似乎无法获得
{"files": [
{
"name": "picture1.jpg",
"size": 902604,
"url": "http:\/\/example.org\/files\/picture1.jpg",
"thumbnailUrl": "http:\/\/example.org\/files\/thumbnail\/picture1.jpg",
"deleteUrl": "http:\/\/example.org\/files\/picture1.jpg",
"deleteType": "DELETE"
},
{
"name": "picture2.jpg",
"size": 841946,
"url": "http:\/\/example.org\/files\/picture2.jpg",
"thumbnailUrl": "http:\/\/example.org\/files\/thumbnail\/picture2.jpg",
"deleteUrl": "http:\/\/example.org\/files\/picture2.jpg",
"deleteType": "DELETE"
}
]}
我一直试图获取每个文件的名称......所以我所做的就是这个。
var obj = JSON.parse(data.result);
for(var i in obj.files){
var urlstring;
urlstring = obj.files[i].name;
alert(urlstring);
}
但不知怎的,它不允许我提醒每个人的名字......我知道我该如何去做呢?
答案 0 :(得分:1)
假设,
var data = {"files": [
{
"name": "picture1.jpg",
"size": 902604,
"url": "http:\/\/example.org\/files\/picture1.jpg",
"thumbnailUrl": "http:\/\/example.org\/files\/thumbnail\/picture1.jpg",
"deleteUrl": "http:\/\/example.org\/files\/picture1.jpg",
"deleteType": "DELETE"
},
{
"name": "picture2.jpg",
"size": 841946,
"url": "http:\/\/example.org\/files\/picture2.jpg",
"thumbnailUrl": "http:\/\/example.org\/files\/thumbnail\/picture2.jpg",
"deleteUrl": "http:\/\/example.org\/files\/picture2.jpg",
"deleteType": "DELETE"
}
]};
尝试,
$.each(data, function(i, items) {
$.each(items, function(j, item) {
alert(item.name);
});
});
<强> Working fiddle Here 强>
您的数据格式错误,因此您需要正确格式化。
请查看以下数据和工作小提琴。
var data = '{"files": ['+
'{"name": "picture1.jpg","size": 902604,"url":"http:\/\/example.org\/files\/picture1.jpg","thumbnailUrl": "http:\/\/example.org\/files\/thumbnail\/picture1.jpg","deleteUrl": "http:\/\/example.org\/files\/picture1.jpg","deleteType": "DELETE"},' +
'{"name":"picture2.jpg","size":841946,"url":"http:\/\/example.org\/files\/picture2.jpg","thumbnailUrl":"http:\/\/example.org\/files\/thumbnail\/picture2.jpg","deleteUrl":"http:\/\/example.org\/files\/picture2.jpg","deleteType":"DELETE"}]}';
var obj = JSON.parse(data);
for(var i in obj.files){
var urlstring;
urlstring = obj.files[i].name;
alert(urlstring);
}