SQL：高级查询

Question

我一直在尝试用几个小时来解决网页上的练习（自学sql），但我无法正常练习。

This is the summary

这是我到目前为止的查询

SELECT p.name, COUNT(trip_no)
FROM Pass_in_trip AS pit
INNER JOIN (
    SELECT r.seat as seat, MAX(r.qty) as qty
    FROM (
        SELECT place AS seat, COUNT(trip_no) AS qty
        FROM Pass_in_trip
        INNER JOIN (
            SELECT place AS seat
            FROM Pass_in_trip
            GROUP BY place
            HAVING COUNT(ID_psg) > 1
        ) AS s
        ON s.seat = place
        GROUP BY ID_psg, place
    ) as r
    GROUP BY r.seat
    HAVING MAX(r.qty) > 1
) as r
ON place = r.seat
INNER JOIN Passenger AS p
ON p.ID_psg = pit.ID_psg
GROUP BY p.name, p.ID_psg, place, r.qty
HAVING COUNT(trip_no) = r.qty

/* This query gives better results than the previous one, however,
it doesn't pass all tests */

SELECT p.name, COUNT(trip_no)
FROM Pass_in_trip AS pit
INNER JOIN (
    SELECT r.seat as seat, MAX(r.qty) as qty
    FROM (
        SELECT place AS seat, COUNT(trip_no) AS qty
        FROM Pass_in_trip
        GROUP BY ID_psg, place
    ) as r
    GROUP BY r.seat
    HAVING MAX(r.qty) > 1
) as r
ON place = r.seat
INNER JOIN Passenger AS p
ON p.ID_psg = pit.ID_psg
GROUP BY p.name, r.qty
HAVING COUNT(trip_no) = r.qty

一些帮助将非常值得赞赏。 最好的问候。

Answer 1

试

SELECT p.name, COUNT(trip_no)
FROM Pass_in_trip AS pit
INNER JOIN (
    SELECT r.seat as seat, MAX(r.qty) as qty
    FROM (
        SELECT place AS seat, COUNT(trip_no) AS qty
        FROM Pass_in_trip
        INNER JOIN (
            SELECT place AS seat
            FROM Pass_in_trip
            GROUP BY place
            HAVING COUNT(ID_psg) > 1
        ) AS s
        ON s.seat = place
        GROUP BY ID_psg, place
    ) as r
    GROUP BY r.seat
    HAVING MAX(r.qty) > 1
) as r
ON place = r.seat
INNER JOIN Passenger AS p
ON p.ID_psg = pit.ID_psg
GROUP BY p.name,trip_no
HAVING COUNT(trip_no) = r.qty