Question

尝试修复代码。我在3号，5号和9号线上拉错了。我很难过。看起来不错，但不是：/

<?php
if($_POST['submit']) {
    if(empty($_POST['name']) || empty($_POST['email']) || empty($_POST[$_POST['comments'])) {
        $error = true;
    }else{

        $to = "theloregame@gmail.com"

        $name = trim($_POST['name']);
        $email = trim($_POST['email']);
        $comments = trim($_POST['comments']);

        $subject = "Contact Form";

        $messages = "name: $name \r\n Email: $email \r\n Comments: $comments";
        $headers = "From:" . $name;
        $mailesent = mail($to, $subject, $messages, $headers);

        if($mailsclient) {
            $sent = true;
        }
    }
}
?>

Answer 1

缺少半结肠

$to = "theloregame@gmail.com"

应该是

$to = "theloregame@gmail.com";
                             ^

和

empty($_POST[$_POST['comments'])

应该是

empty($_POST['comments'])

Answer 2

错误为空（$ _ POST [$ _ POST ['comments']）

   if(empty($_POST['name']) || empty($_POST['email']) || empty($_POST['comments']))

并且缺少分号：

$to = "theloregame@gmail.com";

Answer 3

尝试这个

<?php
if($_POST['submit']) 
{
    if(empty($_POST['name']) || empty($_POST['email']) || empty($_POST['comments'])) 
    {
        $error = true;
    }
  else{

        $to = "theloregame@gmail.com";

        $name = trim($_POST['name']);
        $email = trim($_POST['email']);
        $comments = trim($_POST['comments']);

        $subject = "Contact Form";

        $messages = "name:".$name."\r\n Email:".$email."\r\nComments:".$comments;
        $headers = "From:" . $name;
        $mailesent = mail($to, $subject, $messages, $headers);

        if($mailsclient) 
    {
            $sent = true;
        }
      }
}
?>

错误及其解决方案：

//最后一个条件附近的语法错误$ _POST [$ _ POST

if(empty($_POST['name']) || empty($_POST['email']) || empty($_POST[$_POST['comments']))

更改为：

if(empty($_POST['name']) || empty($_POST['email']) || empty($_POST[$_POST['comments']))

//分号丢失

$to = "theloregame@gmail.com"

更改为：

$to = "theloregame@gmail.com";

//级联

$messages = "name:".$name."\r\n Email:".$email."\r\nComments:".$comments;

Answer 4

 $to = "theloregame@gmail.com";

//你需要;有

一个好的方法是评论代码块，只留下2-3行，看看你是否有错误。如果是，您可以轻松找到它们，如果不是，请再添加2-3行，然后重试。

难倒在代码上

4 个答案: