我使用codeigniter 2.1.4
。
我将会话记录到database1
,然后查询database2
数据。但是会话找不到database2
表。我不想将会话记录到database2
。
错误消息。
A Database Error Occurred
Error Number: 1146
Table 'database2.sessions' doesn't exist
SELECT * FROM (`sessions`) WHERE `session_id` = 'fd384ac44b1fe1c073cfc23185esdfda' AND `user_agent` = 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/29.0.1547.76 Safari/537.36'
Filename: libraries/Session.php
Line Number: 213
我的database.php
。
$active_group = 'default';
$active_record = TRUE;
$db['default']['hostname'] = 'localhost';
$db['default']['username'] = 'root';
$db['default']['password'] = 'password';
$db['default']['database'] = 'database1';
$db['default']['dbdriver'] = 'mysql';
$db['default']['dbprefix'] = '';
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = TRUE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = '';
$db['default']['char_set'] = 'utf8';
$db['default']['dbcollat'] = 'utf8_general_ci';
$db['default']['swap_pre'] = '';
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;
$db['database2']['hostname'] = 'localhost';
$db['database2']['username'] = 'root';
$db['database2']['password'] = 'password';
$db['database2']['database'] = 'database2';
$db['database2']['dbdriver'] = 'mysql';
$db['database2']['dbprefix'] = '';
$db['database2']['pconnect'] = TRUE;
$db['database2']['db_debug'] = TRUE;
$db['database2']['cache_on'] = FALSE;
$db['database2']['cachedir'] = '';
$db['database2']['char_set'] = 'utf8';
$db['database2']['dbcollat'] = 'utf8_general_ci';
$db['database2']['swap_pre'] = '';
$db['database2']['autoinit'] = FALSE;
$db['database2']['stricton'] = FALSE;
我的config.php
$config['sess_cookie_name'] = 'ci_session';
$config['sess_expiration'] = 7200;
$config['sess_expire_on_close'] = FALSE;
$config['sess_encrypt_cookie'] = TRUE;
$config['sess_use_database'] = TRUE;
$config['sess_table_name'] = 'sessions';
$config['sess_match_ip'] = FALSE;
$config['sess_match_useragent'] = TRUE;
$config['sess_time_to_update'] = 300;
这是我的查询database2
代码。
function ip_get($ip) {
$db_rentcar = $this->load->database('rent_car', TRUE);
$db_rentcar->from('ip');
$db_rentcar->where('ip_ip', $ip);
if($db_rentcar->count_all_results() == 1) {
$query = $db_rentcar->get_where('ip', array('ip_ip' => $ip));
return $query->row_array();
} else {
return array('ip_name' => 'user1', 'ip_type' => 1);
}
}
我尝试将此代码添加到Session.php
。
$this->CI->load->database('database1', TRUE);
错误变成了。如何解决问题?感谢。
An Error Was Encountered
You have specified an invalid database connection group.
答案 0 :(得分:3)
您的活动数据库是您在database.php中最后定义的最后一个数据库 要连接下一个,请手动连接,或者如果您总是需要连接,请将其放入My_Controller。
$this->db2 = $this->CI->load->database('db2', TRUE);
供参考,详细了解here
答案 1 :(得分:2)
连接到多个数据库
如果您需要同时连接到多个数据库,可以按照以下步骤操作:
$DB1 = $this->load->database('group_one', TRUE);
$DB2 = $this->load->database('group_two', TRUE);
注意:更改单词" group_one"和" group_two"到您要连接的特定组名(或者您可以传递上面指出的连接值)。
通过将第二个参数设置为TRUE(布尔值),该函数将返回数据库对象。
以这种方式连接时,您将使用对象名称来发出命令,而不是本指南中使用的语法。换句话说,而不是发出命令:
$this->db->query();
$this->db->result();
etc...
您将使用:
$DB1->query();
$DB1->result();
etc...
查看官方文档https://www.codeigniter.com/userguide3/database/connecting.html#connecting-to-multiple-databases
答案 2 :(得分:1)
我找到了答案。
function simple_query($sql)
{
if ( ! $this->conn_id)
{
$this->initialize();
}
$this->db_select(); // Add this code
return $this->_execute($sql);
}
参考here