Question

我的问题不是关于一般游戏算法。当我对“你想继续吗？输入真或假”这个问题回答“是”时，程序输出：

"Player one, throw your shape(rock, paper, scissors)! 
 Player two, throw your shape(rock, paper, scissors)!"

所以我可以在第一个周期输入值，但不能在第二个周期输入值。我该如何解决？感谢。

代码：

public static void main(String[] args) {

        String playerOne;
        String playerTwo;
        Scanner myScan = new Scanner(System.in);
        boolean playAgain = true;

        do 
        {
            System.out.println("Player one, throw your shape(rock, paper, scissors)! ");
            playerOne = myScan.nextLine();        
            System.out.println("Player two, throw your shape(rock, paper, scissors)! ");
            playerTwo = myScan.nextLine();




            if (playerOne.equals("scissors") && playerTwo.equals("rock"))
            {
            System.out.println("Player one lost! Playr two won!");
            } 

              else if (playerOne.equals("scissors") && playerTwo.equals("paper")) 
              {
              System.out.println("Player one won! Player two lost!");
              } 


              else if (playerOne.equals("rock") && playerTwo.equals("paper")) 
              {
               System.out.println("Player one lost! Player two won!");
              }


              else if (playerOne.equals("rock") && playerTwo.equals("scissors")) 
              {
              System.out.println("Player one won! Player two lost!");
              }


              else if (playerOne.equals("paper") && playerTwo.equals("scissors")) 
              {
              System.out.println("Player one lost! Player two won!");
              }


              else if (playerOne.equals("paper") && playerTwo.equals("rock")) 
              {
              System.out.println("Player one won! Player two lost!");
              }

              System.out.println("Do you want to continue? Enter true or false.");
              playAgain = myScan.nextBoolean();

        }while(playAgain);


    }
}

Answer 1

这是因为Scanner只读取您使用nextBoolean请求的布尔值，而不是其他任何内容，甚至不是以下行结束。然后结束的行保留在输入流中，并在循环出现时作为空行返回，并且您要求nextLine。

您要做的是读取完整的行而不仅仅是playAgain的布尔值，并手动解释（建议使用类似myScan.nextLine().equals("yes")的内容）。

在while循环中的第一个循环之后输出

1 个答案: