Question

我一直在谷歌搜索和搜索所有堆栈交换的正确答案，但我似乎无法找到它。我所拥有的是通过popover segue呈现的弹出视图，当在弹出视图中单击按钮时，我希望它被解除并显示UIAlert。这是我到目前为止的代码，以及我从其他答案中收集的代码但是没有工作：

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([segue.identifier isEqualToString:@"popOverSegue"]) {
    if ([segue isKindOfClass:[UIStoryboardPopoverSegue class]]) {
        UIStoryboardPopoverSegue *popoverSegue = (UIStoryboardPopoverSegue *)segue;
        self.myPopoverController = popoverSegue.popoverController;
    }
}
}


- (void)methodThatShouldCauseMyPopoverToCloseAnimated:(BOOL)animated
{
[self.myPopoverController dismissPopoverAnimated:animated];
NSLog(@"Dismissed");
}


-(IBAction)presentPopoverView:(id)sender {
if (!popOverViewIsShown){
    [self performSegueWithIdentifier:@"popOverSegue" sender:self];
    popOverViewIsShown = YES;
}else {
    [self methodThatShouldCauseMyPopoverToCloseAnimated:YES];
    popOverViewIsShown = NO;
}

}

- (IBAction)logoutMethod:(id)sender {

[self methodThatShouldCauseMyPopoverToCloseAnimated:YES];

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Logout"
                                                message:@"Are you sure?"
                                               delegate:self
                                      cancelButtonTitle:@"Cancel"
                                      otherButtonTitles:@"OK", nil];
alert.tag = 0;
[alert show];

}

我怀疑当我致电methodThatShouldCauseMyPopoverToClose myPopoverController等于零时。有什么建议？非常感谢！：）

Answer 1

将这样的popover存储在prepareForSegue中，然后放置一个断点以确保该方法正在触发。

self.myPopoverController = [(UIStoryboardPopoverSegue *)segue popoverController];

使用Storyboard Segues解除Popover视图

1 个答案: