Question

我必须通过坐标获得一个地址，但它不起作用并输出“无法获取地址”：

public String GetAddress(String lat, String lon)
        {
            Geocoder geocoder = new Geocoder(this, Locale.ENGLISH);
            String ret = "";
            try {
                List<Address> addresses = geocoder.getFromLocation(Double.parseDouble(lat), Double.parseDouble(lon), 1);
                if(addresses != null) {
                    Address returnedAddress = addresses.get(0);
                    StringBuilder strReturnedAddress = new StringBuilder("");
                    for(int i=0; i<returnedAddress.getMaxAddressLineIndex(); i++) {
                        strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
                    }
                    ret = strReturnedAddress.toString();
                    ret=ret.substring(0, ret.length() - 1);
                }
                else{
                    ret = "Unknown Address";
                }
            }
            catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
                ret = "Couldn't get Address";
            }
            return ret;
        }

logcat的：

09-27 23:47:49.837: W/System.err(1862): java.io.IOException: Service not Available
09-27 23:47:49.847: W/System.err(1862):     at android.location.Geocoder.getFromLocation(Geocoder.java:136)
09-27 23:47:49.847: W/System.err(1862):     at com.example.free.Add.GetAddress(Add.java:634)
09-27 23:47:49.857: W/System.err(1862):     at com.example.free.Add$LoadAddress.doInBackground(Add.java:608)
09-27 23:47:49.857: W/System.err(1862):     at com.example.free.Add$LoadAddress.doInBackground(Add.java:1)
09-27 23:47:49.857: W/System.err(1862):     at android.os.AsyncTask$2.call(AsyncTask.java:287)
09-27 23:47:49.857: W/System.err(1862):     at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
09-27 23:47:49.857: W/System.err(1862):     at java.util.concurrent.FutureTask.run(FutureTask.java:137)
09-27 23:47:49.857: W/System.err(1862):     at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
09-27 23:47:49.857: W/System.err(1862):     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
09-27 23:47:49.857: W/System.err(1862):     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
09-27 23:47:49.857: W/System.err(1862):     at java.lang.Thread.run(Thread.java:856)

Answer 1

此问题的常见答案是您必须重新启动设备。

当然，您无法告诉用户重启设备以使您的应用程序正常运行，因此我的解决方案是使用HTTP回退，这是我在代码中使用的AsyncTask。

你必须根据你的情况修改它，因为我从位置查找地址而不是相反。

    private class GetAddressPositionTask extends
        AsyncTask<String, Integer, LatLng> {

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }

    @Override
    protected LatLng doInBackground(String... plookupString) {

        String lookupString = plookupString[0];
        final String lookupStringUriencoded = Uri.encode(lookupString);
        LatLng position = null;

        // best effort zoom
        try {
            if (geocoder != null) {
                List<Address> addresses = geocoder.getFromLocationName(
                        lookupString, 1);
                if (addresses != null && !addresses.isEmpty()) {
                    Address first_address = addresses.get(0);
                    position = new LatLng(first_address.getLatitude(),
                            first_address.getLongitude());
                }
            } else {
                Log.e(TAG, "geocoder was null, is the module loaded? "
                        + isLoaded);
            }

        } catch (IOException e) {
            Log.e(TAG, "geocoder failed, moving on to HTTP");
        }
        // try HTTP lookup to the maps API
        if (position == null) {
            HttpGet httpGet = new HttpGet(
                    "http://maps.google.com/maps/api/geocode/json?address="
                            + lookupStringUriencoded + "&sensor=true");
            HttpClient client = new DefaultHttpClient();
            HttpResponse response;
            StringBuilder stringBuilder = new StringBuilder();

            try {
                response = client.execute(httpGet);
                HttpEntity entity = response.getEntity();
                InputStream stream = entity.getContent();
                int b;
                while ((b = stream.read()) != -1) {
                    stringBuilder.append((char) b);
                }
            } catch (ClientProtocolException e) {
            } catch (IOException e) {
            }

            JSONObject jsonObject = new JSONObject();
            try {
                // Log.d("MAPSAPI", stringBuilder.toString());

                jsonObject = new JSONObject(stringBuilder.toString());
                if (jsonObject.getString("status").equals("OK")) {
                    jsonObject = jsonObject.getJSONArray("results")
                            .getJSONObject(0);
                    jsonObject = jsonObject.getJSONObject("geometry");
                    jsonObject = jsonObject.getJSONObject("location");
                    String lat = jsonObject.getString("lat");
                    String lng = jsonObject.getString("lng");

                    // Log.d("MAPSAPI", "latlng " + lat + ", "
                    // + lng);

                    position = new LatLng(Double.valueOf(lat),
                            Double.valueOf(lng));
                }

            } catch (JSONException e) {
                Log.e(TAG, e.getMessage(), e);
            }

        }
        return position;
    }

    @Override
    protected void onPostExecute(LatLng result) {
        Log.i("GEOCODE", result.toString());
        super.onPostExecute(result);
    }

};

Google Geocoder服务不可用（要处理的坐标）

1 个答案: