请有人告诉我哪里错了?运行脚本时出现以下错误:
解析错误:语法错误,第32行的C:\ wamp \ www \ baljeet2 \ ViewAllPolicy1.php中的意外T_VARIABLE
这是我的完整代码:
<!DOCTYPE html>
<html>
<body bgcolor='white'>
<?PHP
include 'config.php';
session_start();
//if ($_SESSION['auth']!='TRUE') {
//header ("Location: ../a_login.php");
//}
?>
<?PHP
$con=mysqli_connect($host,$user,$pass,$DB_name);
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
else
{
echo "";
}
$result = mysqli_query($con,"SELECT * FROM policydetail1");
echo "pass<br>";
int $num_rows=0;
$num_rows= mysql_num_rows($result);
if ($num==0) {
// Show message
echo "No record Found";
} else {
// do your while stuff here
while($row = mysqli_fetch_array($result))
{
echo $row['CompanyName']." ".$row['PolicyNo']." ".$row['OD']." ".$row['ThirdParty']." ".$row['ServiceTaxRate']." ".$row['TotalAmount']." ".$row['Discount']." ".$row['CommissionRate']." ".$row['Commission']." ".$row['CommissionStatus']." ".$row['Date']."<br>";
}
}
mysqli_close($con);
//echo "<div align='center'><div style='background-color:#4682B4; color:white; width:1000px; height:30px; text-align:center; font-family:trebuchet ms;'>Policy Add Succefully!!!</div></div><br> <div align='center'><a href='Add Policy Form.html'>Add more records</a><a href='Add Policy Form.html'> <BR>Back to Main Menu</a></div>";
?>
我是PHP新手并且很难找到这个错误。第32行的代码如下:
int $num_rows=0; //Here I am getting error
我还检查了分号和语法,但没有找到。
答案 0 :(得分:3)
Php是动态类型语言。这意味着变量没有类型。运行时是否以变量内容为基础知道类型。
<?php
$var = 0; echo gettype($var); // integer
$str = 'str'; echo gettype($str); // string
$boo = false; echo gettype($boo$); // boolean
如果需要,可以施放值:
<?php
$integer = '3'; // now is a string
$number = 2 * (int)$integer; // '3' becomes an integer with (int)
echo $number; // will print 6
答案 1 :(得分:1)
int
不是PHP中的关键字。所以它将其解释为变量名称。然后紧接着另一个变量名称($num_rows
),这是解析器不期望的。
我认为你的意思是:
$num_rows = 0;
您无需声明变量类型。解释器将在需要时识别类型。