我试图以递归方式通过Active Directory获取用户的所有直接报告。 因此,对于一个用户,我最终会得到一个列表,其中列出了所有将此人作为经理或者有一个人作为经理的人,他们有一个人作为经理......他最终将输入用户作为经理。
我目前的尝试相当缓慢:
private static Collection<string> GetDirectReportsInternal(string userDN, out long elapsedTime)
{
Collection<string> result = new Collection<string>();
Collection<string> reports = new Collection<string>();
Stopwatch sw = new Stopwatch();
sw.Start();
long allSubElapsed = 0;
string principalname = string.Empty;
using (DirectoryEntry directoryEntry = new DirectoryEntry(string.Format("LDAP://{0}",userDN)))
{
using (DirectorySearcher ds = new DirectorySearcher(directoryEntry))
{
ds.SearchScope = SearchScope.Subtree;
ds.PropertiesToLoad.Clear();
ds.PropertiesToLoad.Add("directReports");
ds.PropertiesToLoad.Add("userPrincipalName");
ds.PageSize = 10;
ds.ServerPageTimeLimit = TimeSpan.FromSeconds(2);
SearchResult sr = ds.FindOne();
if (sr != null)
{
principalname = (string)sr.Properties["userPrincipalName"][0];
foreach (string s in sr.Properties["directReports"])
{
reports.Add(s);
}
}
}
}
if (!string.IsNullOrEmpty(principalname))
{
result.Add(principalname);
}
foreach (string s in reports)
{
long subElapsed = 0;
Collection<string> subResult = GetDirectReportsInternal(s, out subElapsed);
allSubElapsed += subElapsed;
foreach (string s2 in subResult)
{
result.Add(s2);
}
}
sw.Stop();
elapsedTime = sw.ElapsedMilliseconds + allSubElapsed;
return result;
}
本质上,此函数将一个可分辨的名称作为输入(CN = Michael Stum,OU = test,DC = sub,DC = domain,DC = com),并且对此,对ds.FindOne()的调用很慢
我发现搜索userPrincipalName要快得多。我的问题:sr.Properties [“directReports”]只是一个字符串列表,这就是distinguishedName,它似乎很难搜索。
我想知道,有没有一种快速的方法来在distinguishedName和userPrincipalName之间进行转换?或者,如果我只使用distinguishedName来搜索用户有更快的方法吗?
编辑:感谢您的回答!搜索Manager-Field将功能从90秒提高到4秒。这是新的和改进的代码,它更快,更易读(请注意,elapsedTime功能中很可能存在错误,但函数的实际核心有效):
private static Collection<string> GetDirectReportsInternal(string ldapBase, string userDN, out long elapsedTime)
{
Collection<string> result = new Collection<string>();
Stopwatch sw = new Stopwatch();
sw.Start();
string principalname = string.Empty;
using (DirectoryEntry directoryEntry = new DirectoryEntry(ldapBase))
{
using (DirectorySearcher ds = new DirectorySearcher(directoryEntry))
{
ds.SearchScope = SearchScope.Subtree;
ds.PropertiesToLoad.Clear();
ds.PropertiesToLoad.Add("userPrincipalName");
ds.PropertiesToLoad.Add("distinguishedName");
ds.PageSize = 10;
ds.ServerPageTimeLimit = TimeSpan.FromSeconds(2);
ds.Filter = string.Format("(&(objectCategory=user)(manager={0}))",userDN);
using (SearchResultCollection src = ds.FindAll())
{
Collection<string> tmp = null;
long subElapsed = 0;
foreach (SearchResult sr in src)
{
result.Add((string)sr.Properties["userPrincipalName"][0]);
tmp = GetDirectReportsInternal(ldapBase, (string)sr.Properties["distinguishedName"][0], out subElapsed);
foreach (string s in tmp)
{
result.Add(s);
}
}
}
}
}
sw.Stop();
elapsedTime = sw.ElapsedMilliseconds;
return result;
}
答案 0 :(得分:10)
首先,如果您已经拥有要查找的DN,则无需将范围设置为“子树”。
此外,如何查找“manager”属性是您查找的人的所有对象,然后迭代它们。这应该通常比其他方式更快。</ p>
(&(objectCategory=user)(manager=<user-dn-here>))
编辑:以下内容非常重要,但到目前为止只在答案的评论中提到过:
如上所述构建过滤器字符串时,存在使用对DN有效但在过滤器中具有特殊含义的字符将其分解的风险。这些must be escaped:
* as \2a
( as \28
) as \29
\ as \5c
NUL as \00
/ as \2f
// Arbitrary binary data can be represented using the same scheme.
编辑:将SearchRoot
设置为对象的DN,将SearchScope
设置为Base
也是将单个对象拉出AD的快速方法。