select new FeedResource
{
Title = (string)details.Element("title"),
Host = (string)details.Element("link"),
Description = (string)details.Element("description"),
PublishedOn = (DateTime?)details.Element("pubDate"),
Generator = (string)details.Element("generator"),
Language = (string)details.Element("language")
}
在上面的代码中我想将类型转换值传递给另一个函数, 示例
Description = getValidDescription((string) details.Element("description"))
但我无法实现任何投入?
注意:类型转换需要处理空值(如果“description”没有值,则它(XElement)将完美地处理null。
答案 0 :(得分:0)
为我工作得很好;什么是错误消息?例如:
// doesn't have to be static - just simpler for my test
static string getValidDescription(string description)
{
// handle nulls safely (could return a default here)
if (description == null) return null;
// for example only...
return CultureInfo.CurrentCulture.TextInfo
.ToTitleCase(description);
}
var qry =
from details in doc.Root.Elements("detail")
select new FeedResource
{
Title = (string)details.Element("title"),
Host = (string)details.Element("link"),
Description = getValidDescription((string) details.Element("description")),
PublishedOn = (DateTime?)details.Element("pubDate"),
Generator = (string)details.Element("generator"),
Language = (string)details.Element("language")
};