Question

我有一个空终止并动态分配的名为'text_buff'的字符串，其中包含单词“bar”。我想用我选择的另一个单词替换这个单词，这个单词可以比原单单词更长或更短。

这是我的代码到现在为止，我似乎无法弄清楚我做错了什么。

        char * toswap = "newword";
        int diff = strlen(toswap)-strlen("bar");
        int wlocation = strstr(text_buff,"bar")-text_buff;
        if (diff > 0) {
            text_buff = realloc(text_buff,strlen(text_buff)+diff);
            for (i=strlen(text_buff) ; i > wlocation+strlen("bar") -1; --i ){
                text_buff[i+diff] = text_buff[i];
            }
            for (i = 0 ; i < strlen("bar")+1; ++i){
                text_buff[wlocation+i] = toswap[i];

            }
        } else if (diff < 0){
                for (i=wlocation+diff ; i <strlen(text_buff);++i ){
                    text_buff[i]=text_buff[i-diff];
                }
                for (i = 0 ; i < strlen("bar")+1; ++i){
                    text_buff[wlocation+i] = toswap[i];
                }
}

Answer 1

插入新单词时出现错误的循环条件：

        for (i = 0 ; i < strlen("bar")+1; ++i){
            text_buff[wlocation+i] = toswap[i];
        }

应该是：

        for (i = 0 ; i < strlen(toswap); ++i){
            text_buff[wlocation+i] = toswap[i];
        }

除此之外，您缺少错误处理。如果这是学校作业，你可以在没有错误处理的情况下进行管理。

Answer 2

你忘了最后一个'\ 0'的1个字符;

text_buff = realloc(text_buff,strlen(text_buff)+diff);

应该是

text_buff = realloc(text_buff,strlen(text_buff)+diff + 1);

替换字符串中的单个单词

2 个答案: