Question

嘿，我是PHP的OO的新手，但我知道基本的Java并且在Java中理解OO，但我正在尝试理解如何通过OO将其与HTML正确地交织在一起。为什么以下代码不会回复消息？感谢。

<?php

class SubmitPost {

    public function __construct() {
        $Db = new PDO('mysql:host=localhost;dbname=Comment', 'root', '');
    }

    public function Comment($Post, $Time, $Title) {

        $Post = strip_tags($_POST['Post']);
        $Time = time();
        $Title = strip_tags($_POST['Title']);

            $Messages = array('success' => 'Your comment has been added.', 'error' => 'There was a problem adding your comment.');

                if(isset($Post, $Title)) {
                    return $Messages['success'];
                } else {
                    return $Messages['error'];
                }

    }
}

$New = new SubmitPost;
var_dump($New);
?>

<html>
    <head>
    </head>

    <body>
        <form action="OO.php" method="POST">
            <input type="text" name="Title" placeholder="Your Title"><br />
            <textarea placeholder="Your Comment" name="Post"></textarea><br />
            <input type="submit" value="Comment">
        </form>
    </body>
</html>

Answer 1

你需要在某个地方调用你的方法。

$New = new SubmitPost();
echo $New->Comment("needless","because","unused");  // You are not using these values in your method
//var_dump($New);

修改那不是真正的OOP。它应该像

public function Comment($Post, $Time, $Title) { $Post = strip_tags($Post); $Title = strip_tags($Title); //.... }

并将其称为

$New = new SubmitPost(); echo $New->Comment($_POST["Post"],time(),$_POST["Title"]);

Answer 2

您的对象中没有任何内容。这就是为什么你没有得到任何输出。请尝试以下代码：

<?php

class SubmitPost {
    public $test;
    public function __construct() {
        $Db = new PDO('mysql:host=localhost;dbname=comment', 'root', '');
        $this->test = "yahoo";
    }

    public function Comment($Post, $Time, $Title) {

        $Post = strip_tags($_POST['Post']);
        $Time = time();
        $Title = strip_tags($_POST['Title']);

            $Messages = array('success' => 'Your comment has been added.', 'error' => 'There was a problem adding your comment.');

                if(isset($Post, $Title)) {
                    return $Messages['success'];
                } else {
                    return $Messages['error'];
                }

    }
}

$New = new SubmitPost;
var_dump($New);

我的PHP OOP在哪里错了？

2 个答案: