Question

我的数据是这样的：

Smith, Bob; Data; More Data
Doe, John; Data; More Data

如果你看下面你会看到我正在尝试将FullName分成第一个和最后一个。错误是：

“String类型中的方法split（String）不适用于参数（char）”

String line = scanner.nextLine();
String[] data = line.split(";");
String[] fullName = data[0].split(',');

Answer 1

我在my comment中解释过，错误很容易修复：','→","。

我将简要介绍一下为何会出现这种情况。在Java中，'中包含的单个字符为character literals，与string literals中的split()非常不同。例如，如果您来自Python世界，这可能需要一些时间才能习惯，因为"和'可以基本上同义使用。

在任何情况下，"的单参数{{3}}方法只接受一个String，而String又被解析为正则表达式。这就是你需要双引号的原因。

Answer 2

将单引号切换为双引号

String[] fullName = data[0].split(",");

Answer 3

String.split(String)将String作为唯一参数。

public String[] split(String regex)

    Splits this string around matches of the given regular expression.

    This method works as if by invoking the two-argument split method with the
    given expression and a limit argument of zero. Trailing empty strings are
    therefore not included in the resulting array.

    The string "boo:and:foo", for example, yields the following results with
    these expressions:

        Regex   Result
        :   { "boo", "and", "foo" }
        o   { "b", "", ":and:f" }

    Parameters:
        regex - the delimiting regular expression 
    Returns:
        the array of strings computed by splitting this string around matches
        of the given regular expression 
    Throws:
        PatternSyntaxException - if the regular expression's syntax is invalid
    Since:
        1.4
    See Also:
        Pattern

Java string.split是一个拆分字符串

3 个答案: