好的，所以我尝试在这个程序的对话框中实现一个计时器，暂停一秒钟，然后继续进行下一个对话。当我尝试这样做时，java会发出错误，例如：非法启动表达，预期，.class预期，并在解析时到达文件末尾。当我尝试在屏幕上显示特定时间的对话时，如何实现计时器以使窗口不冻结？并且不要告诉我Thread.sleep（）因为我试过了，它所做的就是冻结应用程序。
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.util.*;
public class RpsNuke extends JFrame
implements ActionListener
{
private final char moves[] = {'R', 'P', 'S', 'N'};
private JRadioButton rock, paper, scissors, nuke;
private JTextField display;
public RpsNuke()
{
super("Rock, Paper, Scissors, Nuke");
rock = new JRadioButton(" Rock ", true);
paper = new JRadioButton(" Paper ");
scissors = new JRadioButton(" Scissors ");
nuke = new JRadioButton(" Nuke ");
ButtonGroup rpsButtons = new ButtonGroup();
rpsButtons.add(rock);
rpsButtons.add(paper);
rpsButtons.add(scissors);
rpsButtons.add(nuke);
JButton go = new JButton(" Go ");
go.addActionListener(this);
display = new JTextField(25);
display.setEditable(false);
display.setBackground(Color.yellow);
Container c = getContentPane();
c.setLayout(new FlowLayout());
c.add(rock);
c.add(paper);
c.add(scissors);
c.add(nuke);
c.add(go);
c.add(display);
if (nuke.isSelected()){
display.setText("Don't do it man");}
else {
display.setText("");}
}
/**
* returns -1 if the player wins,
* 0 if it's a tie, and 1 if the computer wins
*/
private int nextPlay(char computerMove, char playerMove)
{
if ((computerMove == 'R'&&playerMove == 'S')||(computerMove == 'S'&&playerMove=='P')||(computerMove=='P'&&playerMove=='R')){
return 1;}
else if ((computerMove == 'R'&&playerMove == 'R')||(computerMove=='S'&&playerMove=='S')||(computerMove=='P'&&playerMove=='P')){
return 0;}
else if (playerMove == 'N'){
return 2;}
return -1;
}
public void actionPerformed(ActionEvent evt)
{
char playerMove, computerMove;
playerMove = 0;
if (rock.isSelected()){
playerMove = 'R';}
else if (paper.isSelected()){
playerMove = 'P';}
else if (scissors.isSelected()){
playerMove = 'S';}
else if (nuke.isSelected()){
playerMove = 'N';}
int k = (int)(Math.random() * 3);
computerMove = moves[k];
int result = nextPlay(computerMove, playerMove);
String msg = "";
if (result != 2)
{msg = " You said " + makeWord(playerMove) + ", I said " +
makeWord(computerMove);
if (result < 0){
msg += " -- you win.";}
else if (result == 0){
msg += " -- tie.";}
else if (result > 0){
msg += " -- I win.";}
}
if (result == 2)
{
TimerTask tasknew = new TimerScheduleFixedRateDelay();
Timer timer = new Timer();
// scheduling the task at fixed rate delay
timer.scheduleAtFixedRate(tasknew,1000,1000);
@Override
}
// this method performs the task
public void run() {
msg = "It's too late, we're all dead!";
msg = "...";
msg = "Look at what you did, there's nothing left.";
msg = "Looks like we have to start over again...";
window.setVisible(false);
main(null);
}
display.setText(msg);
}
private String makeWord(char move)
{
String word = "";
switch (move)
{
case 'R': word = "rock"; break;
case 'P': word = "paper"; break;
case 'S': word = "scissors"; break;
case 'N': word = "nuke"; break;
}
return word;
}
public static void main(String[] args) //Here
{
RpsNuke window = new RpsNuke();
window.setBounds(300, 300, 400, 140);
window.setDefaultCloseOperation(EXIT_ON_CLOSE);
window.setVisible(true);
}
} //And here
答案 0 :(得分：4)
这似乎是你问题的开始......
if (result == 2) {
TimerTask tasknew = new TimerScheduleFixedRateDelay();
Timer timer = new Timer();
// scheduling the task at fixed rate delay
timer.scheduleAtFixedRate(tasknew, 1000, 1000);
@Override
}
public void run() {
没有名为TimerScheduleFixedRateDelay的类，Timer没有默认构造函数，您似乎没有声明tasknew，我不知道为什么{{1} }出现在这里......
让我们首先评论那些
@Override下一个问题是你错过了一个结束括号......
if (result == 2) {
//TimerTask tasknew = new TimerScheduleFixedRateDelay();
//Timer timer = new Timer();
// scheduling the task at fixed rate delay
//timer.scheduleAtFixedRate(tasknew, 1000, 1000);
//@Override
}
public void run() {
看起来应该更像......
if (result == 2) {
...
}
// Something is amiss here...
public void run() {
下一步...
if (result == 2) {
...
}
}
public void run() {
public void run() {
msg = "It's too late, we're all dead!";
msg = "...";
msg = "Look at what you did, there's nothing left.";
msg = "Looks like we have to start over again...";
window.setVisible(false);
main(null);
}
display.setText (msg);
未定义，msg未定义且window未定义且main正在方法上下文之外调出，这是非法的......
display.setText很容易修复public void run() {
String msg = "It's too late, we're all dead!";
msg = "...";
msg = "Look at what you did, there's nothing left.";
msg = "Looks like we have to start over again...";
display.setText (msg);
//window.setVisible(false);
//main(null);
}
，不确定msg，但由于它正在使用display.setText，我认为它属于msg方法而且我有不知道run和window仍然需要解决...
这引导我们进入......
main哦，我想我发现了我们丢失的大括号去了....这意味着上面代码中第一个大括号}
private String makeWord(char move)
{
String word = "";
switch (move)
{
case 'R': word = "rock"; break;
case 'P': word = "paper"; break;
case 'S': word = "scissors"; break;
case 'N': word = "nuke"; break;
}
return word;
}
public static void main(String[] args) //Here
{
RpsNuke window = new RpsNuke();
window.setBounds(300, 300, 400, 140);
window.setDefaultCloseOperation(EXIT_ON_CLOSE);
window.setVisible(true);
}
} //And here
以下的所有内容实际上都是在}之外定义的，对于这个问题的背景，这是非法的......
所以，让我们评论一下......
class在那里，事情看起来更“好”......我也认为我找到了//}
private String makeWord(char move)
{
String word = "";
switch (move)
{
case 'R': word = "rock"; break;
case 'P': word = "paper"; break;
case 'S': word = "scissors"; break;
case 'N': word = "nuke"; break;
}
return word;
}
public static void main(String[] args) //Here
{
RpsNuke window = new RpsNuke();
window.setBounds(300, 300, 400, 140);
window.setDefaultCloseOperation(EXIT_ON_CLOSE);
window.setVisible(true);
}
} //And here
，但它在window中被定义......不是很有帮助;）
基于查看代码，我认为您应该避免使用main并使用java.util.Timer，这将阻止您从事件调度线程的内容之外更新UI，这是另一个你可能希望避免的一堆蠕虫...