将两个T-SQL数据透视查询合二为一

时间:2009-12-14 20:14:42

标签: sql sql-server tsql pivot

假设你有这张表:

CREATE TABLE Records
(
    RecordId       int IDENTITY(1,1) NOT NULL,
    CreateDate     datetime          NOT NULL,
    IsSpecial      bit               NOT NULL
    CONSTRAINT PK_Records   PRIMARY KEY(RecordId)
)

现在需要创建一个报告,其中总记录和总特殊记录按月细分。我可以单独使用这两个查询:

--      TOTAL RECORDS PER MONTH
SELECT January, February, March, April, May, June,
    July, August, September, October, November, December
FROM (
    SELECT RecordId, DATENAME(MONTH, CreateDate) AS RecordMonth
    FROM dbo.Records
) AS SourceTable
PIVOT (
    COUNT(RecordId) FOR RecordMonth IN (January, February, March, April, May, June,
    July, August, September, October, November, December)
) AS PivotTable;

--      TOTAL SPECIAL RECORDS PER MONTH
SELECT January, February, March, April, May, June,
    July, August, September, October, November, December
FROM (
    SELECT RecordId, DATENAME(MONTH, CreateDate) AS RecordMonth
    FROM dbo.Records
    WHERE IsSpecial = 1
) AS SourceTable
PIVOT (
    COUNT(RecordId) FOR RecordMonth IN (January, February, March, April, May, June,
    July, August, September, October, November, December)
) AS PivotTable;

结果可能如下所示:

                  Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec
total              0     0    2     2     1      0     0    1      2     1     2    4
total special      0     0    1     0     1      0     0    0      0     0     0    2 

是否可以将这两个查询合并为一个更有效的查询?

3 个答案:

答案 0 :(得分:3)

我会这样做:

SELECT
     CASE SQ.total_type
          WHEN 1 THEN 'total special'
          WHEN 2 THEN 'total expensive'
          ELSE 'total'
     END AS total_type,
     SUM(CASE WHEN MONTH(R.CreateDate) = 1 THEN 1 ELSE 0 END) AS January,
     SUM(CASE WHEN MONTH(R.CreateDate) = 2 THEN 1 ELSE 0 END) AS February,
     SUM(CASE WHEN MONTH(R.CreateDate) = 3 THEN 1 ELSE 0 END) AS March,
     ...
FROM
     dbo.Records R
INNER JOIN
     (
          SELECT 0 AS total_type UNION ALL   -- All
          SELECT 1 UNION ALL                 -- IsSpecial
          SELECT 2                           -- IsExpensive
     ) AS SQ ON
     (R.IsSpecial | (R.IsExpensive * 2)) & SQ.total_type = SQ.total_type
GROUP BY
     SQ.total_type
ORDER BY
     SQ.total_type DESC

答案 1 :(得分:2)

每个数据透视表只能有一个聚合(COUNT(RecordId)),因此您所做的只是将一个结果集与一个UNION ALL组合在一起,并使用合适的额外列来标识每个数据透视图。

否则,您无法区分数据透视表中的两个不同聚合

答案 2 :(得分:0)

感谢汤姆的解决方案,它解决了我的支点问题。

对我来说太糟糕了,我提出了错误的问题。对于我的问题,我现在觉得最好使用像这样的普通分组查询:

SELECT DATENAME(MONTH, CreateDate) AS Month,
    COUNT(*) AS Total,
    SUM(CASE
        WHEN IsSpecial = 1 THEN 1
        ELSE 0
    END) AS TotalSpecial,
    SUM(CASE
        WHEN IsExpensive = 1 THEN 1
        ELSE 0
    END) AS TotalExpensive
FROM Records
GROUP BY DATENAME(MONTH, CreateDate);

然后剩下要做的就是在结果出现之前旋转结果。很高兴知道呃?