我想对上一小时内启动的流程的平均持续时间,名称和ID进行排序,按15分钟的步长进行排序和分组
以下是我的表格:
过程
processRun
这是我的SQL查询:
WITH tps AS (
SELECT sysdate-1/24,trunc(TO_DATE((trunc(sysdate,'MI')-MOD(TO_CHAR(sysdate, 'MI'),15)/(24*60))-1/24) + (level) / 96, 'mi') AS DATEREF
FROM dual
CONNECT BY level <= 96 * (TO_DATE(SYSDATE) - TO_DATE(((trunc(sysdate,'MI')-MOD(TO_CHAR(sysdate, 'MI'),15)/(24*60))-1/24)-1/24))
),
da AS (
SELECT p.id as Id, p.Name as Nom,trunc(pRun.DateStart,'MI') as dateStart, AVG(pRun.DATEEND - pRun.DATESTART)*1440 as VAL
FROM process p
JOIN processrun pRun ON pRun.processid = p.id
WHERE trunc(pRun.DateStart,'MI') BETWEEN trunc(SYSDATE-1/24,'MI') AND trunc(SYSDATE,'MI')
AND p.Id = 92
)
SELECT da.Id, da.Nom, da.VAL, da.dateStart, tps.dateref
FROM tps
LEFT JOIN da ON da.dateStart BETWEEN tps.dateref AND tps.dateref-15/1440
GROUP BY tps.dateref
ORDER BY da.dateStart, da.Nom ASC
这导致:
SELECT da.Id, da.Nom, da.VAL, da.dateStart, tps.dateref
ERROR at line 13:
ORA-00979: not a GROUP BY expression
(*
指针位于da.Id
)
我知道我没有正确地执行此操作,但我想将结果分组10分钟,我真的不知道如何使用WITH
子句来修复它。通常情况下,我只会使用GROUP BY tps.dateref
,但它无效。
感谢您的帮助!
知道了!由于我的GROUP BY
,我的AVG()
是假的。我想出了如何通过juste在上一次AVG()
选择我的SELECT
来解决这个问题。这是我现在的查询:
WITH tps AS (
SELECT trunc(TO_DATE((trunc(sysdate,'MI')-MOD(TO_CHAR(sysdate, 'MI'),15)/(24*60))-1/24) + (level) / 96, 'mi') AS DATEREF
FROM dual
CONNECT BY level <= 96 * (TO_DATE(SYSDATE) - TO_DATE(((trunc(sysdate,'MI')-MOD(TO_CHAR(sysdate, 'MI'),15)/(24*60))-1/24)-1/24))
),
da AS (
SELECT p.id as Id, p.Name as Nom,trunc(pRun.DateStart,'MI') as dateStart, pRun.DATEEND - pRun.DATESTART as VAL
FROM process p
JOIN processrun pRun ON pRun.processid = p.id
WHERE trunc(pRun.DateStart,'MI') BETWEEN trunc(SYSDATE-1/24,'MI') AND trunc(SYSDATE,'MI')
AND p.Id = 92
)
SELECT da.Id,da.Nom, AVG(da.VAL)*1440,tps.dateref
FROM tps
LEFT JOIN da ON da.dateStart BETWEEN tps.dateref-15/1440 AND tps.dateref
GROUP BY da.Id, da.Nom, tps.dateref
ORDER BY tps.dateref, da.Nom ASC