Question

#!/bin/bash

# When a match is not found, just present nothing.
shopt -s nullglob

# Match all .wav files containing the date format.
files=(*[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]*.wav)

if [[ ${#files[@]} -eq 0 ]]; then
 echo "No match found."
fi

for file in "${files[@]}"; do
 # We get the date part by part
 file_date=''
 # Sleep it to parts.
 IFS="-." read -ra parts <<< "$file"
 for t in "${parts[@]}"; do
        # Break from the loop if a match is found
    if [[ $t == [0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9] ]]; then
        file_date=$t
        break
     fi
  done
 # If a value was not assigned, then show an error message and continue to the next file.
 # Just making sure there is nothing in Array and date before it moves on
 if [[ -z $file_date ]]; then
    unset $files
    continue
fi

file_year=${file_date:0:4}
file_month=${file_date:4:2}

echo $file_year
echo $file_month
echo mkdir -p $file_year/$file_month
mkdir -p "$file_year/$file_month"

 # -- is just there to not interpret filenames starting with - as options.

echo "$file" "$file_year/$file_month" 
mv  "$file" "$file_year/$file_month"
done

所以在运行我的代码之后，我的输出就是这个我的DIR 201211,201212,201301,201302,201303,201304，所以我尝试运行这个因为我有YYYYMMDD的文件并且想要制作DIR年份然后在里面我想要DIR月份然后提交。有时我可以得到一个DIR2013 / 06 /文件，但由于一些奇怪的原因我得到DIR201304 /文件。我不明白这个问题是什么.......我在大约1.1 Terabite上运行这个脚本

Answer 1

bash可以做正则表达式，所以你可以这样做：

filename="blah.blah-12345678.ext"
if [[ $filename =~ [.-]([0-9]{4})([0-9]{2})[0-9]{2}[.-] ]]; then 
    echo year=${BASH_REMATCH[1]} month=${BASH_REMATCH[2]}
fi

year=1234 month=56

BASH_REMATCH是一个数组，用于保存索引0中字符串的匹配部分，其他索引保存括号中捕获的部分。

轻微的DIR错误

1 个答案: