Question

我陷入了非常奇怪的问题。我有2个模型User和Supplier。用户可以添加许多供应商，所以这里是我的模型的样子。这是我的用户模型

class User < ActiveRecord::Base
.
.
.
     has_many :suppliers, dependent: :destroy

     def Supplier_feed
         Supplier.where("user_id = ?", id)
     end
end

我的供应商模型就像

class Supplier < ActiveRecord::Base
    set_primary_key :id 

  belongs_to :user
  default_scope -> { order('created_at DESC') }
  validates :supplier, presence: true, length: { maximum: 140 }
  validates :user_id, presence: true
end

我的控制器看起来像

class SuppliersController < ApplicationController
   before_filter :signed_in_user, only: [:index, :edit, :update, :destroy]


  def index
    @user=current_user
    @supplier = current_user.suppliers.paginate(page: params[:page])
  end

  def new
    @supplier=Supplier.new
  end


  def create
    @supplier = current_user.suppliers.build(supplier_params)
    if @supplier.save
      flash[:success] = "Supplier created!"
      redirect_to root_url
    else
      @supplier_feed_items = []
      render 'users/home'
    end
  end

  def destroy
  end

  private

      def supplier_params
      params.require(:suppliers).permit(:supplier)
    end
end

当我尝试添加某个供应商时，我收到了错误

 TypeError in SuppliersController#create

can't convert Symbol into String

以下是我的表单的样子。

<%= form_for :suppliers, :url => {:action => "create"} do |f| %>

  <div class="field">
    <%= f.text_area :supplier, placeholder: "Add new Supplier..." %>
  </div>
  <%= f.submit "Post", class: "btn btn-large btn-primary" %>
<% end %>

因为我是RoR的新手，我无法弄清楚我做了什么错。请指导我正确的方向。提前致谢

修改我的应用程序跟踪就像

app/controllers/suppliers_controller.rb:32:in `supplier_params'
app/controllers/suppliers_controller.rb:16:in `create'

This error occurred while loading the following files:
   supplier

我的请求参数是

{"utf8"=>"✓",
 "authenticity_token"=>"1op5Kkh6EXO+wsR9TmAY1SW3ZIUNYcrodbJ9lfpJjck=",
 "suppliers"=>{"supplier"=>"abc"},
 "commit"=>"Post"}

这是我的添加供应商表格。

<%= form_for :suppliers, :url => {:action => "create"} do |f| %> 
  <div class="field">
    <%= f.text_area :supplier, placeholder: "Add new Supplier..." %>
  </div>
  <%= f.submit "Post", class: "btn btn-large btn-primary" %>
<% end %>

我正在使用偏见。所以这是我的观点供应商

<div class="span8">
    <% if @user.suppliers.any? %>
      <h3>Suppliers (<%= @user.suppliers.count %>)</h3>
      <ol class="supplierss">
        <%= render @supplier %>
      </ol>
      <%= will_paginate @supplier %>
    <% end %>
  </div>

这是我的_Suppliers.html.erb

<li>
  <span class="content"><%= supplier.supplier %></span>
  </span>
</li>

Answer 1

这是视图中的拼写错误

您已使用

def new
   @supplier=Supplier.new
end

在视图中你已经使用了

<%= form_for :suppliers, :url => {:action => "create"} do |f| %>

视图:suppliers中的

必须supplier从s删除suppliers

请使用

def new
  @supplier=Supplier.new
end

<%= form_for :supplier, :url => {:action => "create"} do |f| %>

  <div class="field">
    <%= f.text_area :supplier, placeholder: "Add new Supplier..." %>
  </div>
  <%= f.submit "Post", class: "btn btn-large btn-primary" %>
<% end %>

Answer 2

您可以创建一个这样的表单

<%= form_for @supplier do |f| %>

并在控制器中

def create

@supplier = current_user.suppliers.build(params[:supplier])

无法在轨道上将符号转换为字符串ruby

2 个答案: